Chemistry - Class Twelve

Solutions

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Solution of NCERT In Text Questions – 2.6

Question - 2.6 - H 2S, a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of H2 S in water at STP is 0.195 m, calculate Henry❜s law constant.

Solution:

Given, Solubility of H2 S in water at STP = 0.195 m

This means, moles of H2 S = 0.195

Moles of Solutions class 12 chemistry - NCERT In Text Solution31

Now mole fraction of Solutions class 12 chemistry - NCERT In Text Solution32

Solutions class 12 chemistry - NCERT In Text Solution33

Now, According to Henry’s Law Solutions class 12 chemistry - NCERT In Text Solution34

We, know that, pressure (p) at STP = 0.987 bar

Solutions class 12 chemistry - NCERT In Text Solution35

Thus, Henry❜s Law constant KH = 282 bar

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Topics covered in this chapter of Solutions

1. Solutions

2. Types of Solutions

3. Solutions - Concentration

4. Solution of NCERT In Text Questions

Class 12 Biology

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