Linear Equations in One Variable - 8th math
NCERT Exercise 2.2 Solution
Question (1): If you subtract
Solution:
Let the required number is n.
Now, according to question, we have
After dividing both sides by 1/2 we get,
After transposing – 1/2 to RHS we get,
Thus, required number
Alternate method
Let the required number is n.
Now, according to question, we have
After transposing 1/2 to RHS, we get
Now, after transposing 1/2 to RHS, we get
Thus, required number
Question (2) The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?
Solution:
Given, perimetre of the rectangular swimming pool = 154 m
And Length = 2 m more than twice of the breadth.
Let the breadth of the swimming pool = b metre
∴ Length of the swimming pool = 2 b m + 2 metre
Thus, Length and breadth of the given swimming pool = ?
We know that, Perimetre of a Rectangle = 2 (length + breadth)
∴ 154 = 2 [ (2b + 2) + b ]
⇒ 154 = 2(2 b + 2 + b )
⇒ 154 = 2 (3 b + 2 )
⇒ 154 = 6 b + 4
After subtracting 4 from both sides, we get
⇒ 154 – 4 = 6 b + 4 – 4
⇒ 150 m = 6 b
After dividing both sides by 6, we get
⇒ 25 = b
Therefore, breaadth (b) = 25 m
Now, since length = 2 b + 2
Therefore, by substituting the value of breadth (b), we get
2 × 25 + 2 m= 50 + 2 = 52
Thus, length of the given pool = 52 m And breadth = 25 m Answer
Question (3) The base of an isosceles triangle is 4/3 cm The perimeter of the triangle is
Solution:
Given,
Base of the isosceles triangle =
And, Perimeter
Thus, length of the remaining equal sides = ?
We know that, Isosceles triangles have two sides equal.
Now, We know that,
Perimeter of an isosceles triangle = Sum of two equal sides + third side
Let the length of equal sides of the given isosceles triangle = a
And length of unequal side = b
Therefore, Perimeter = 2a + b
Therefore,
After transposing 4/3 to RHS, we get
After transposing 2 to RHS, we get
Thus, length of the one of the equal sides = 7/5 cm Answer
Question (4) Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
Solution:
Given, sum of two numbers = 95
One of number exceeds other by 15
Therefore, numbers = ?
Let one number is a
Therefore, according to question second number = a + 15
Now, as given in the question, sum of two numbers = 95
Therefore,
a + a + 15 = 95
⇒ 2a + 15 = 95
By transposing 15 to RHS, we get
⇒ 2a = 95 – 15
⇒ 2 a = 80
After dividing both sides by 2, we get
⇒ a=40
Now, since second number = a + 15
Therefore, by substituting the value of a we get
The second number = 40 + 15 = 55
Thus, first number = 40 and second number = 55 Answer
Question (5) Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?
Solution:
Given, ratio of the two numbers = 5:3
And their difference = 18
Therefore, numbers = ?
Let first number = 5x
And second number = 3x
As per question, 5x – 3x = 18
⇒ 2x = 18
After dividing both sides by 2, we get
⇒ x = 9
Now, we have first number = 5 x = 5 × 9
Thus, first number = 45
And, we have the second number = 3 x = 3 × 9
Thus, second number = 27
Thus, required numbers are 45 and 27 Answer
Question (6) Three consecutive integers add up to 51. What are these integers?
Solution:
Given, the sum of three consecutive integers = 51
Therefore, integers = ?
Let the first integer = a
Therefore, second consecutive integer = a + 1
And, third consecutive integer = a + 2
Since, according to question sum of the given three consecutive number = 51
Therefore,
a + (a +1) + (a + 2) = 51
⇒ a + a + 1 + a + 2 = 51
After rearranging the above expression
⇒ a + a + a + 1 + 2 = 51
⇒ 3a + 1 + 2 = 51
⇒ 3a + 3 = 51
After transposing 3 to the RHS, we get
3a = 51 – 3
⇒ 3a = 48
After dividing both sides by 3, we get
⇒ a =16
Now, the first integer = 16
Therefore, next two consecutive integers
= 16 + 1 = 17 and 17 + 1 = 18
Thus, required three consecutive integers are 16, 17 and 18 Answer
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