🏡 Home
    1. Linear Equations in One Variable
    2. Understanding Quadrilaterals
    3. Practical Geometry
    4. Mensuration
    1. Math
    2. Chemistry
    3. Chemistry Hindi
    4. Biology
    5. Exemplar Solution
    1. 11th physics
    2. 11th physics-hindi
    1. Science 10th (English)
    2. Science 10th (Hindi)
    3. Mathematics
    4. Math (Hindi)
    5. Social Science
    1. Science (English)
    2. 9th-Science (Hindi)
    1. 8th-Science (English)
    2. 8th-Science (Hindi)
    3. 8th-math (English)
    4. 8th-math (Hindi)
    1. 7th Math
    2. 7th Math(Hindi)
    1. Sixth Science
    2. 6th Science(hindi)
    1. Five Science
    1. Science (English)
    2. Science (Hindi)
    1. Std 10 science
    2. Std 4 science
    3. Std two EVS
    4. Std two Math
    5. MCQs Math
    6. एमoसीoक्यूo गणित
    7. Civil Service
    1. General Math (Hindi version)
    1. About Us
    2. Contact Us
10upon10.com

Linear Equations in One Variable - 8th math

8th-math-home

8th-math hindi-home

NCERT Exercise 2.2 Solution


Question (1): If you subtract from a number and multiply the result by , you get . What is the number?

Solution:

Let the required number is n.

Now, according to question, we have

After dividing both sides by 1/2 we get,

After transposing – 1/2 to RHS we get,

Thus, required number Answer

Alternate method

Let the required number is n.

Now, according to question, we have

After transposing 1/2 to RHS, we get

Now, after transposing 1/2 to RHS, we get

Thus, required number Answer

Question (2) The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?

Solution:

Given, perimetre of the rectangular swimming pool = 154 m

And Length = 2 m more than twice of the breadth.

Let the breadth of the swimming pool = b metre

∴ Length of the swimming pool = 2 b m + 2 metre

Thus, Length and breadth of the given swimming pool = ?

We know that, Perimetre of a Rectangle = 2 (length + breadth)

∴ 154 = 2 [ (2b + 2) + b ]

⇒ 154 = 2(2 b + 2 + b )

⇒ 154 = 2 (3 b + 2 )

⇒ 154 = 6 b + 4

After subtracting 4 from both sides, we get

⇒ 154 – 4 = 6 b + 4 – 4

⇒ 150 m = 6 b

After dividing both sides by 6, we get

⇒ 25 = b

Therefore, breaadth (b) = 25 m

Now, since length = 2 b + 2

Therefore, by substituting the value of breadth (b), we get

2 × 25 + 2 m= 50 + 2 = 52

Thus, length of the given pool = 52 m And breadth = 25 m Answer

Question (3) The base of an isosceles triangle is 4/3 cm The perimeter of the triangle is cm. What is the length of either of the remaining equal sides?

Solution:

Given,

Base of the isosceles triangle = cm

And, Perimeter cm

Thus, length of the remaining equal sides = ?

We know that, Isosceles triangles have two sides equal.

Now, We know that,

Perimeter of an isosceles triangle = Sum of two equal sides + third side

Let the length of equal sides of the given isosceles triangle = a

And length of unequal side = b

Therefore, Perimeter = 2a + b

Therefore,

After transposing 4/3 to RHS, we get

After transposing 2 to RHS, we get

cm

Thus, length of the one of the equal sides = 7/5 cm Answer

Question (4) Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.

Solution:

Given, sum of two numbers = 95

One of number exceeds other by 15

Therefore, numbers = ?

Let one number is a

Therefore, according to question second number = a + 15

Now, as given in the question, sum of two numbers = 95

Therefore,

a + a + 15 = 95

⇒ 2a + 15 = 95

By transposing 15 to RHS, we get

⇒ 2a = 95 – 15

⇒ 2 a = 80

After dividing both sides by 2, we get

⇒ a=40

Now, since second number = a + 15

Therefore, by substituting the value of a we get

The second number = 40 + 15 = 55

Thus, first number = 40 and second number = 55 Answer

Question (5) Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?

Solution:

Given, ratio of the two numbers = 5:3

And their difference = 18

Therefore, numbers = ?

Let first number = 5x

And second number = 3x

As per question, 5x – 3x = 18

⇒ 2x = 18

After dividing both sides by 2, we get

⇒ x = 9

Now, we have first number = 5 x = 5 × 9

Thus, first number = 45

And, we have the second number = 3 x = 3 × 9

Thus, second number = 27

Thus, required numbers are 45 and 27 Answer

Question (6) Three consecutive integers add up to 51. What are these integers?

Solution:

Given, the sum of three consecutive integers = 51

Therefore, integers = ?

Let the first integer = a

Therefore, second consecutive integer = a + 1

And, third consecutive integer = a + 2

Since, according to question sum of the given three consecutive number = 51

Therefore,

a + (a +1) + (a + 2) = 51

⇒ a + a + 1 + a + 2 = 51

After rearranging the above expression

⇒ a + a + a + 1 + 2 = 51

⇒ 3a + 1 + 2 = 51

⇒ 3a + 3 = 51

After transposing 3 to the RHS, we get

3a = 51 – 3

⇒ 3a = 48

After dividing both sides by 3, we get

⇒ a =16

Now, the first integer = 16

Therefore, next two consecutive integers

= 16 + 1 = 17 and 17 + 1 = 18

Thus, required three consecutive integers are 16, 17 and 18 Answer




Reference: