Linear Equations in One Variable - 8th math

Question (6) 8x + 4 = 3 (x – 1) + 7

Solution:

Given, 8x + 4 = 3(x – 1) + 7

⇒ 8x + 4 = 3x – 3 + 7

⇒ 8x + 4 = 3x + 4

After transposing 4 to RHS, we get

⇒ 8x = 3x + 4 –4

After transposing 3x to LHS, we get

⇒ 8x – 3x = 4 – 4

⇒ 5x = 0

After transposing 5 to RHS, we get

⇒ x = 0/5 = 0

Thus, x = 0 Answer

CHECKING OF RESULT:

Given, 8x + 4 = 3x + 4

Now, LHS = 8x + 4

After substituting the value of x = 0 in LHS we get

8 × 0 + 4

⇒ LHS = 4

Now, RHS = 3x + 4

After substituting the value of x = 0 in RHS we get

3 × 0 + 4

⇒ RHS = 4

Thus, LHS = RHS proved.

Question (7) x = 4/5 (x + 10)

Solution:

Given, x = 4/5 (x + 10)

After transposing to LHS, we get

After transposing 5 to RHS, we get, or by cross multiplication, we get

x = 8 × 5

⇒ x = 40 Answer

CHECKING OF RESULT:

Given, x = 4/5 (x + 10)

RHS

After substituting the value of x = 40 in RHS we get

= 4 × 10 = 40

⇒ RHS = 40

Now, since LHS = x = 40

Thus, LHS = RHS Proved

Question (8)

Solution

Given,

After transposing 1 to RHS, we get

Now, after transposing to LHS, we get

After transposing 15 to RHS, we get

3x = 2 × 15

⇒ 3x = 30

After transposing 3 to RHS, we get

x = 30/3

⇒ x = 10 Answer

CHECKING OF RESULT:

Given,

LHS

After substituting the value of x = 10 in LHS, we get

LHS

Now, RHS

After substituting the value of x = 10 in RHS, we get

RHS

Thus, LHS = RHS Proved

Question (9) 2y + 5/3 = 26/3 – y

Solution:

Given, 2y + 5/3 = 26/3 – y

After transposing 5/3 to RHS we get

2y = 26/3 – y – 5/3

After transposing –y to LHS, we get

3y = 7

After transposing 3 to RHS, we get

y = 7/3 Answer