Linear Equations in One Variable - 8th math
NCERT Solution Exercise 2.5
Solve the following linear equations.
Question (1)
Solution
Given,
After transposing –1/5 to RHS, we get
After transposing x/3 to LHS, we get
After cross multiplication, we get
20x = 9 × 6
⇒ 20x = 54
After transposing 20 to RHS, we get
Checking of Result
Given,
Now, LHS
Now, after substituting the value of
Thus, LHS
Now, RHS =
Now, after substituting the value of
Thus, RHS
Thus, LHS = RHS Proved
Thus,
Question (2)
Solution:
Given
After cross multiplication, we get
⇒ 7n = 21 × 12
⇒ 7n = 252
After transposing 7 to RHS, we get
⇒ n = 36
Checking of Result
Given
Now, after substituting the value of n = 36 in LHS, we get
= 18 – 27 + 30
= 21 = RHS
Thus, LHS = RHS Proved
Thus, n = 36 Answer
Question (3)
Solution
Given,
After transposing
Again after transposing 7 to RHS, we get
After multiplying both sides by 6 we get
⇒ 5x = –25
After transposing 5 to RHS, we get
⇒ x = –5
Checking of Result
Given,
Now, LHS =
After substituting the value of x = –5 in this LHS, we get
Thus, LHS =
Now, RHS =
After substituting the value of x = –5 in this RHS, we get
Thus, RHS =
Thus, LHS = RHS Proved
Thus, x = –5 Answer
Question (4)
Solution
Given,
After cross multiplication, we get
5(x – 5) = 3(x – 3)
⇒ 5x – 25 = 3x – 9
After transposing –25 to RHS, we get
5x = 3x – 9 + 25
After transposing 3x to LHS, we get
5x – 3x = – 9 + 25
⇒ 2x = 16
After transposing 2 to RHS, we get
x = 16/2 = 8
⇒ x = 8 Answer
Checking of Result
Given,
We have LHS =
Now, after substituting the value of x = 8 in the LHS, we get
Thus, LHS = 1
Now, RHS =
Now, after substituting the value of x = 8 in the RHS, we get
Thus, RHS = 1
Thus, LHS = RHS Proved
Question (5)
Solution:
Given,
After transposing –t to LHS, we get
After cross multiplication, we get
3(13t – 18) = 2 × 12
⇒ 39t – 54 = 24
After transposing –54 to RHS, we get
39t = 24 + 54
⇒ 39t = 78
After transposing 39 to RHS, we get
t = 78/39 = 2
⇒ t = 2 Answer
Checking of Result
Given,
Now, LHS
After substituting the value of t = 2 in this LHS, we get
Thus, LHS =
Now, RHS =
After substituting the value of t = 2 in this LHS, we get
Thus, RHS
Thus, LHS = RHS Proved
Reference: