Practical Geometry - 8th math
NCERT Exercise 4.3
Construction of quadrilateral when two adjacent sides and three angles are known
Class 8 math Practical Geometry Construction of quadrilateral when two adjacent sides and three angles are knownSolution of NCERT Exercise 4.3 Question (1) Construct the following quadrilaterals
(i) Quadrilateral MORE
MO = 6 cm
OR = 4.5 cm
∠M = 600
∠O = 1050
∠R = 1050
Solution
First of all construct a rough sketch of the given quadrilateral.
Step (i) First of all to draw the side MO = 6 cm. Draw a horizontal line and cut 6 cm from it using a compass and a measuring scale.
Step (ii) On the point O an angle of 105o is made.
Step (iii) On the side OR an arc of radius 4.5 cm is drawn. This the side OR = 4.5cm
Step (iv) On point R on the side OR the given angle 105o is made.
Step (v) Now, draw an angle equal to 60o on point M and stretch the line upto ray of angle made on point R to complete the given quadrilateral.
This is the construction of given quadrilateral.
Class 8 math Practical Geometry Construction of quadrilateral Solution of NCERT Exercise 4.3 Question (1) (ii) Quadrilateral PLAN
PL = 4 cm
LA 6.5 cm
∠P = 90o
∠A = 10o
∠N = 85o
Solution
First of all a rough sketch of the given quadrilateral is drawn to estimate the construction.
Here, since angle L is not given thus, without knowing the angle L it is not possible to draw the given quadrilateral because ∠L is the angle made between given adjacent sides.
Now, we know that, sum of measure of angles of a quadrilateral = 3600
Thus, 85o + 90o + ∠L + 110o = 360o
⇒ 285o + ∠L = 360o
⇒ ∠L = 360o – 285o
Step (i) Draw a horizontal line and cut it equal to 4 cm using a compass and a measuring scale.
Step(ii) Make an angle equal to
Step (iii) Measure a length of
Step (iv) Draw and angle equal to 110o on point A and draw a line for this angle.
Step (v) Draw an angle equal to 90o on point P. And draw a line which meets on point N, i.e. AN to complete the given quadrilateral.
This is the construction of given quadrilateral.
Class 8 math Practical Geometry Construction of quadrilateral Solution of NCERT Exercise 4.3 Question (1) (iii) Parallelogram HEAR
HE = 5 cm
EA = 6 cm
∠R = 850
Solution
First of all a rough sketch of the given parallelogram is drawn to estimate the construction of given parallelogram.
Here, as given ∠R = 85o
And we know that, opposite angles of a parallelogram are equal in measurement.
Here, since ∠E is the opposite angle of ∠R
Thus, ∠E = ∠R
Thus, ∠E = 85o
Now, we know that, the sum of adjacent angles of a parallelogram is equal = 180o
Thus, ∠R + ∠H = 180o
⇒ 85o + ∠H = 180o
⇒ ∠H = 180o – 85o
⇒ ∠H = 95o
Step (i) To draw the side HE = 5 cm of the given parallelogram, a horizontal line is drawn and cut it using a compass and measuring scale equal to 5 cm.
Step (ii) Angle E = 85o is drawn on point E using a protector.
Step (iii) And using a compass an arc of radius 6 cm is made on the ray of angle made on point E
Step (iv) Mark an arc of radius 6 cm on the ray coming out from the point E at an angle of 85o. And name this point as A.
Step (v) Draw and angle equal to 95o on point H and draw a line for this angle.
Since AE||HR
And, we know that the opposite sides of a parallelogram are equal in measure.
Thus, HR = EA = 6 cm
Step (vi) Mark an arc of radius 6cm on line coming out from the point H. Name this point as R.
Step (vii) Now draw a line to connect point R and A to complete the given quadrilateral.
This is the construction of given quadrilateral.
Class 8 math Practical Geometry Construction of quadrilateral Solution of NCERT Exercise 4.3 Question (1) (iv) Rectangle OKAY
OK = 7 cm
KA = 5 cm
Solution
First of all a rough sketch of the given rectangle is made to estimate the construction.
We know that, a rectangle has all angles equal to 90o. And opposite sides are equal.
Step (i) Draw a horizontal line and cut it equal to 7 cm using a compass and a measuring scale.
Step (ii) Draw an angle equal to 90o at point K and draw a line for this angle.
Step (iii) Draw and arc of radius 5 cm on the line of the angle of 90o made on point K. And mark the point of arc meeting at line as A. This is side KA = 5cm.
Step (iv) Draw an angle equal to 90o at point P and draw a line for this angle. Because in a rectangle opposite sides are parallel and angle made by the side of rectangle is equal to 90o.
Step (v) Draw and arc of radius 5 cm on the line of the angle of 90o made on point O. And mark the point of arc meeting at line as Y. This is side OY = 5cm. Because opposite side of a rectangle are equal.
Step (vi) Join the point Y and A and complete the rectangle. This is side YA = 7cm
This is the construction of given rectangle.
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