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Understanding Quadrilaterals - 8th math

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NCERT Exercise 3.1


Understanding Quadrilaterals NCERT Exercise 3.1 Question (1) Given here are some figures.

Classify each of them on the basis of the following.

(a) Simple curve

(b) Simple closed curve

(c) Polygon

(d) Convex polygon

(e) Concave polygon

Solution

(a) Simple curve: figure 1, 2, 5, 6 and 7

(b) Simple closed curve: figure 1, 2, 5, 6 and 7

(c) Polygon: figure 1 and 2

(d) Convex polygon: Figure 2

(e) Concave polygon: figure 1

Understanding Quadrilaterals NCERT Exercise 3.1 Question (2) How many diagonals does each of the following have?

(a) A convex quadrilateral

(b) A regular hexagon

(c) A triangle

Solution

(a) A convex quadrilateral

A convex quadrilateral has two diagonals.

(b) A regular hexagon

A regular hexagon has total 9 (nine) diagonals.

(c) A triangle

A triangle does not have any diagonals. That is a triangle has 0 (zero) diagonal.

Understanding Quadrilaterals NCERT Exercise 3.1 Question (3) What is the sum of the measures of the angles of a convex quadrilateral? Will this property hold if the quadrilateral is not convex? (Make a non-convex quadrilateral and try!)

Solution

The sum of the measures of the angles of a convex quadrilateral is equal to 3600.

A quadrilateral which is not convex also holds the same property. This means the sum of the measures of the angles of a concave quadrilateral is equal to 3600 also.

For concave quadrilateral

A convex quadrilateral also has number of sides equal = 4

And we know that the sum of angles of a polygon

Where n = number of sides

Thus, in a quadrilateral which has 4 sides, the sum of angles And we know that the sum of angles of a polygon

= 2 × 1800

= 3600

Thus, sum of angles of a quadrilateral whether it is a convex or concave = 3600

Understanding Quadrilaterals NCERT Exercise 3.1 Question (4) Examine the table. (Each figure is divided into triangles and the sum of the angles deduced from that).

What can you say about the angle sum of a convex polygon with number of sides?

(a) 7       (b) 8       (c) 10       (d) n

Solution

From the given figures it can be deduced that angle sum of a polygon having n number of sides = (n–2) × 1800

(a) Number of sides = 7

Thus, angle sum of polygon having number of sides equal to 7 = (7 – 2) × 1800

= 5 × 1800

= 9000 Answer

(b) Number of sides = 8

Thus, angle sum of polygon having number of sides equal to 8 = (8 – 2) × 1800

= 6 × 1800

= 10800 Answer

(c) Number of sides = 10

Thus, angle sum of polygon having number of sides equal to 10 = (10 – 2) × 1800

= 8 × 1800

= 14400 Answer

(d) Number of sides = n

Thus, angle sum of polygon having number of sides equal to n

= (n – 2) × 1800 Answer

Understanding Quadrilaterals NCERT Exercise 3.1 Question (5) What is a regular polygon?

State the name of a regular polygon of

(i) 3 sides

(ii) 4 sides

(iii) 6 sides

Solution

Equiangular and equilateral polygons are known as regular polygons.

(i) 3 sides

Polygon with 3 sides is known as a triangle Answer

(ii) 4 sides

Polygon with 4 sides is known as a quadrilateral Answer

(iii) 6 sides

Polygon with 6 sides is known as a hexagon Answer

Understanding Quadrilaterals NCERT Exercise 3.1 Question (6) Find the angle measure x in the following figures.

(a)

Solution

Given, three angles of a quadrilateral = 500, 1300 and 1200 respectively

Then fourth angle (x) = ?

We know that, angle sum of a quadrilateral = 3600

Therefore, The angle sum of the given quadrilateral

= 500 + 1300 + 1200 + x = 3600

⇒ 3000 + x = 3600

⇒ x = 3600 – 3000

⇒ x = 600

Therefore, fourth angle (x) of the given quadrilateral = 600 Answer

(b)

Solution

Here, in the given quadrilateral,

Angle c = 700

Angle B = 600

And angle MAD = 900

Thus, angle (x) = angle D = ?

Since, angle MAD = 900

Thus, angle DAB will be = 900 [∵ angle MAD and angle DAB both form a straight line]

Now, we know that, angle sum of a quadrilateral = 3600

Thus, in the given quadrilateral

∠ DAB + ∠ B + ∠ C + ∠D = 3600

⇒ 900 + 600 + 700 + x = 3600

⇒ 2200 + x = 3600

⇒ x = 3600 – 2200

⇒ x = 1400

Thus, angle x of the given quadrilateral = 1400 Answer

(c)

Solution

In the given, pentagon

Angle G = 300

Angle DAE = 700

Angle CBF = 600

And angle D = angle C = x

Thus, angle x = ?

In between angle DEA and angle CBF

Since angle DAE and angle DAB form a straight line and hence are supplemetary

Thus, angle DAE + angle DAB = 1800

⇒ 700 + ∠ DAB = 1800

⇒ ∠ DAB = 1800 – 700

⇒ &#DAB = 1100

In between angle ABC and angle CBF

Both the angles ABC and CBF form a straight line, and hence are supplementary

Thus, ∠ ABC + ∠ CBF = 1800

⇒ ∠ ABC + 600 = 1800

⇒ ∠ ABC = 1800 – 600

⇒ ∠ ABC = 1200

Now, we know that, angle sum of a pentagon = 5400

Thus, in the given pentagon,

∠ G + ∠ D + ∠ DAB + ∠ ABC + ∠C = 5400

⇒ 300 + x + 1100 + 1200 + x = 5400

⇒ 2600 + 2x = 5400

2x = 5400 – 2600

2x = 2800

x = 1400

Thus, the unknown angle x of given pentagon = 1400 Answer

(d)

Solution

In the given pentagon all sides are equal,

Thus all the angles will also be equal and will be = x

Thus, angle x = ?

Now, we know that, angle sum of a pentagon = 5400

Thus, in the given pentagon,

x + x + x + x + x = 5400

5x = 5400

x = 1080

Thus, the unknown angle x of given pentagon = 1080 Answer

Understanding Quadrilaterals NCERT Exercise 3.1 Question (7)

(a) Find x + y + x.

Solution

Now, we know that sum of exterior angles of a polygon = 3600

Thus, in the given triangle angle x + y + x = 3600 Answer

Alternate method

Given, two angles of the given triangle = 300 and 900

Thus, sum of exterior angles x + y + z = ?

Between angles x and 900

Both the angles form a straight line, and hence are supplementary

Thus, angle x + 900 = 1800

x = 1800 – 900

x = 900

Between angles z and 300

Both the angles form a straight line, and hence are supplementary

Thus, angle z + 300 = 1800

z = 1800 – 300

z = 1500

Now we know that, sum of all the interior angles of a triangle = 1800

Thus, in the given triangle,

∠ CAE + ∠ ABF + ∠ ACB = 1800

⇒ 300 + ∠ ABF + 900 = 1800

⇒ ∠ ABF + 1200 = 1800

⇒ ∠ ABF = 1800 – 1200

⇒ ∠ ABF = 600

Now between angles ABF and ABE

Both the angles ABF and ABE forms a straight line and hence are supplementary

Thus, ∠ ABF + ∠ ABE = 1800

⇒ 600 + y = 1800

⇒ y = 1800 – 600

⇒ y = 1200

Now, x + y + z = 900 + 1200 + 1500

x + y + z = 3600 Answer

(b) Find x + y + x + w

Solution

Given, x, y , z and w are exterior angles of the given quadrilateral.

Thus, x + y + x + w = ?

We know that, sum of exterior angles of a polygon = 3600

Thus, in the given, quadrilateral,

x + y + x + w = 3600 Answer

Alternate Method

Given, three angles of a quadrilateral are 1200, 800 and 600

Then find the sum of exterior angles of given quadrilateral,

i.e. x + y + z + w = ?

In between angles z and 600

Both the angles form a straight line, and thus are supplementary.

Thus, z + 600 = 1800

⇒ z = 1800 – 600

⇒ z = 1200

In between angles y and 800

Both the angles form a straight line, and thus are supplementary.

Thus, y + 800 = 1800

⇒ y = 1800 – 800

⇒ y = 1000

In between angles x and 1200

Both the angles form a straight line, and thus are supplementary.

Thus, x + 1200 = 1800

⇒ x = 1800 – 1200

⇒ y = 600

Now, we know that, sum of angle of a quadrilateral = 3600

Thus, In the given quadrilateral,

∠ HAB + 1200 + 800 + 600 = 3600

⇒ ∠ HAB + 2600 = 3600

⇒ ∠ HAB = 3600 – 2600

⇒ ∠ HAB = 1000

In between angles w and ∠ HAB

Both the angles form a straight line, and thus are supplementary.

Thus, w + ∠ HAB = 1800

Thus, w + 1000 = 1800

⇒ w = 1800 – 1000

⇒ w = 800

Now, in the given quadrilateral,

w + x + y + x

= 800 + 600 + 1000 + 1200

= 3600

Thus, w + x + y + x = 3600 Answer




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