Question : ( 1 of 10 ) Find the average of odd numbers from 5 to 1201
(A) 5.25 किलोमीटर या 5250 मीटर(B) 21 किलोमीटर या 21000 मीटर
(C) 13.125 किलोमीटर या 13125 मीटर
(D) 10.5 किलोमीटर या 10500 मीटर
Correct Answer 603
Solution & Explanation
Solution
Method (1) to find the average of the odd numbers from 5 to 1201
Shortcut Trick to find the average of the given continuous odd numbers
The odd numbers from 5 to 1201 are
5, 7, 9, . . . . 1201
After observing the above list of the odd numbers from 5 to 1201 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 5 to 1201 form an Arithmetic Series.
In the Arithmetic Series of the odd numbers from 5 to 1201
The First Term (a) = 5
The Common Difference (d) = 2
And the last term (ℓ) = 1201
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the odd numbers from 5 to 1201
= 5 + 1201/2
= 1206/2 = 603
Thus, the average of the odd numbers from 5 to 1201 = 603 Answer
Method (2) to find the average of the odd numbers from 5 to 1201
Finding the average of given continuous odd numbers after finding their sum
The odd numbers from 5 to 1201 are
5, 7, 9, . . . . 1201
The odd numbers from 5 to 1201 form an Arithmetic Series in which
The First Term (a) = 5
The Common Difference (d) = 2
And the last term (ℓ) = 1201
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the odd numbers from 5 to 1201
1201 = 5 + (n – 1) × 2
⇒ 1201 = 5 + 2 n – 2
⇒ 1201 = 5 – 2 + 2 n
⇒ 1201 = 3 + 2 n
After transposing 3 to LHS
⇒ 1201 – 3 = 2 n
⇒ 1198 = 2 n
After rearranging the above expression
⇒ 2 n = 1198
After transposing 2 to RHS
⇒ n = 1198/2
⇒ n = 599
Thus, the number of terms of odd numbers from 5 to 1201 = 599
This means 1201 is the 599th term.
Finding the sum of the given odd numbers from 5 to 1201
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given odd numbers from 5 to 1201
= 599/2 (5 + 1201)
= 599/2 × 1206
= 599 × 1206/2
= 722394/2 = 361197
Thus, the sum of all terms of the given odd numbers from 5 to 1201 = 361197
And, the total number of terms = 599
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given odd numbers from 5 to 1201
= 361197/599 = 603
Thus, the average of the given odd numbers from 5 to 1201 = 603 Answer
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