Question : Find the average of odd numbers from 9 to 447
Correct Answer 228
Solution & Explanation
Solution
Method (1) to find the average of the odd numbers from 9 to 447
Shortcut Trick to find the average of the given continuous odd numbers
The odd numbers from 9 to 447 are
9, 11, 13, . . . . 447
After observing the above list of the odd numbers from 9 to 447 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 9 to 447 form an Arithmetic Series.
In the Arithmetic Series of the odd numbers from 9 to 447
The First Term (a) = 9
The Common Difference (d) = 2
And the last term (ℓ) = 447
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the odd numbers from 9 to 447
= 9 + 447/2
= 456/2 = 228
Thus, the average of the odd numbers from 9 to 447 = 228 Answer
Method (2) to find the average of the odd numbers from 9 to 447
Finding the average of given continuous odd numbers after finding their sum
The odd numbers from 9 to 447 are
9, 11, 13, . . . . 447
The odd numbers from 9 to 447 form an Arithmetic Series in which
The First Term (a) = 9
The Common Difference (d) = 2
And the last term (ℓ) = 447
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the odd numbers from 9 to 447
447 = 9 + (n – 1) × 2
⇒ 447 = 9 + 2 n – 2
⇒ 447 = 9 – 2 + 2 n
⇒ 447 = 7 + 2 n
After transposing 7 to LHS
⇒ 447 – 7 = 2 n
⇒ 440 = 2 n
After rearranging the above expression
⇒ 2 n = 440
After transposing 2 to RHS
⇒ n = 440/2
⇒ n = 220
Thus, the number of terms of odd numbers from 9 to 447 = 220
This means 447 is the 220th term.
Finding the sum of the given odd numbers from 9 to 447
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given odd numbers from 9 to 447
= 220/2 (9 + 447)
= 220/2 × 456
= 220 × 456/2
= 100320/2 = 50160
Thus, the sum of all terms of the given odd numbers from 9 to 447 = 50160
And, the total number of terms = 220
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given odd numbers from 9 to 447
= 50160/220 = 228
Thus, the average of the given odd numbers from 9 to 447 = 228 Answer
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