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Math MCQs


Question :    Find the average of odd numbers from 11 to 1419


Correct Answer  715

Solution & Explanation

Solution

Method (1) to find the average of the odd numbers from 11 to 1419

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 11 to 1419 are

11, 13, 15, . . . . 1419

After observing the above list of the odd numbers from 11 to 1419 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 11 to 1419 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 11 to 1419

The First Term (a) = 11

The Common Difference (d) = 2

And the last term (ℓ) = 1419

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 11 to 1419

= 11 + 1419/2

= 1430/2 = 715

Thus, the average of the odd numbers from 11 to 1419 = 715 Answer

Method (2) to find the average of the odd numbers from 11 to 1419

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 11 to 1419 are

11, 13, 15, . . . . 1419

The odd numbers from 11 to 1419 form an Arithmetic Series in which

The First Term (a) = 11

The Common Difference (d) = 2

And the last term (ℓ) = 1419

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 11 to 1419

1419 = 11 + (n – 1) × 2

⇒ 1419 = 11 + 2 n – 2

⇒ 1419 = 11 – 2 + 2 n

⇒ 1419 = 9 + 2 n

After transposing 9 to LHS

⇒ 1419 – 9 = 2 n

⇒ 1410 = 2 n

After rearranging the above expression

⇒ 2 n = 1410

After transposing 2 to RHS

⇒ n = 1410/2

⇒ n = 705

Thus, the number of terms of odd numbers from 11 to 1419 = 705

This means 1419 is the 705th term.

Finding the sum of the given odd numbers from 11 to 1419

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 11 to 1419

= 705/2 (11 + 1419)

= 705/2 × 1430

= 705 × 1430/2

= 1008150/2 = 504075

Thus, the sum of all terms of the given odd numbers from 11 to 1419 = 504075

And, the total number of terms = 705

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 11 to 1419

= 504075/705 = 715

Thus, the average of the given odd numbers from 11 to 1419 = 715 Answer


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