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Math MCQs


Question :    Find the average of even numbers from 8 to 1468


Correct Answer  738

Solution & Explanation

Solution

Method (1) to find the average of the even numbers from 8 to 1468

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 8 to 1468 are

8, 10, 12, . . . . 1468

After observing the above list of the even numbers from 8 to 1468 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 8 to 1468 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 8 to 1468

The First Term (a) = 8

The Common Difference (d) = 2

And the last term (ℓ) = 1468

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 8 to 1468

= 8 + 1468/2

= 1476/2 = 738

Thus, the average of the even numbers from 8 to 1468 = 738 Answer

Method (2) to find the average of the even numbers from 8 to 1468

Finding the average of given continuous even numbers after finding their sum

The even numbers from 8 to 1468 are

8, 10, 12, . . . . 1468

The even numbers from 8 to 1468 form an Arithmetic Series in which

The First Term (a) = 8

The Common Difference (d) = 2

And the last term (ℓ) = 1468

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 8 to 1468

1468 = 8 + (n – 1) × 2

⇒ 1468 = 8 + 2 n – 2

⇒ 1468 = 8 – 2 + 2 n

⇒ 1468 = 6 + 2 n

After transposing 6 to LHS

⇒ 1468 – 6 = 2 n

⇒ 1462 = 2 n

After rearranging the above expression

⇒ 2 n = 1462

After transposing 2 to RHS

⇒ n = 1462/2

⇒ n = 731

Thus, the number of terms of even numbers from 8 to 1468 = 731

This means 1468 is the 731th term.

Finding the sum of the given even numbers from 8 to 1468

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 8 to 1468

= 731/2 (8 + 1468)

= 731/2 × 1476

= 731 × 1476/2

= 1078956/2 = 539478

Thus, the sum of all terms of the given even numbers from 8 to 1468 = 539478

And, the total number of terms = 731

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 8 to 1468

= 539478/731 = 738

Thus, the average of the given even numbers from 8 to 1468 = 738 Answer


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