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Math MCQs


Question :    Find the average of even numbers from 12 to 1310


Correct Answer  661

Solution & Explanation

Solution

Method (1) to find the average of the even numbers from 12 to 1310

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 12 to 1310 are

12, 14, 16, . . . . 1310

After observing the above list of the even numbers from 12 to 1310 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 12 to 1310 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 12 to 1310

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 1310

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 12 to 1310

= 12 + 1310/2

= 1322/2 = 661

Thus, the average of the even numbers from 12 to 1310 = 661 Answer

Method (2) to find the average of the even numbers from 12 to 1310

Finding the average of given continuous even numbers after finding their sum

The even numbers from 12 to 1310 are

12, 14, 16, . . . . 1310

The even numbers from 12 to 1310 form an Arithmetic Series in which

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 1310

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 12 to 1310

1310 = 12 + (n – 1) × 2

⇒ 1310 = 12 + 2 n – 2

⇒ 1310 = 12 – 2 + 2 n

⇒ 1310 = 10 + 2 n

After transposing 10 to LHS

⇒ 1310 – 10 = 2 n

⇒ 1300 = 2 n

After rearranging the above expression

⇒ 2 n = 1300

After transposing 2 to RHS

⇒ n = 1300/2

⇒ n = 650

Thus, the number of terms of even numbers from 12 to 1310 = 650

This means 1310 is the 650th term.

Finding the sum of the given even numbers from 12 to 1310

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 12 to 1310

= 650/2 (12 + 1310)

= 650/2 × 1322

= 650 × 1322/2

= 859300/2 = 429650

Thus, the sum of all terms of the given even numbers from 12 to 1310 = 429650

And, the total number of terms = 650

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 12 to 1310

= 429650/650 = 661

Thus, the average of the given even numbers from 12 to 1310 = 661 Answer


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