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Simple Interest
Math MCQs


Question :    Sandra took a loan of $6900 at the rate of 9% simple interest per annum. If he paid an amount of $12489 to clear the loan, then find the time period of the loan.


Correct Answer  9

Solution & Explanation

Solution

Given,

Principal (P) = $6900

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $12489

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $12489 – $6900 = $5589

Thus, Simple Interest = $5589

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 5589/6900 × 9

= 558900/62100

= 9 years (using formula)

Thus, Time (T) = 9 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $6900

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $5589 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $6900

= 9/100 × 6900

= 9 × 6900/100

= 62100/100 = 621

Thus, simple Interest for 1 year = $621

Now,

∵ If the simple Interest is $621, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/621 years

∴ If the simple Interest is $5589, then the time = 1/621 × 5589 years

= 1 × 5589/621 years

= 5589/621 = 9 years

Thus, time (T) = 9 years Answer


Similar Questions

(1) What amount will be due after 2 years if Richard borrowed a sum of $3300 at a 6% simple interest?

(2) Calculate the amount due after 10 years if Karen borrowed a sum of $5950 at a rate of 6% simple interest.

(3) Christopher took a loan of $6000 at the rate of 10% simple interest per annum. If he paid an amount of $10800 to clear the loan, then find the time period of the loan.

(4) Margaret took a loan of $6700 at the rate of 9% simple interest per annum. If he paid an amount of $12127 to clear the loan, then find the time period of the loan.

(5) Calculate the amount due after 9 years if Jennifer borrowed a sum of $5250 at a rate of 2% simple interest.

(6) Calculate the amount due if Jessica borrowed a sum of $3750 at 3% simple interest for 4 years.

(7) Find the amount to be paid if Jessica borrowed a sum of $5750 at 6% simple interest for 8 years.

(8) How much loan did Jacob borrow 5 years ago at a rate of simple interest 4% per annum, if he paid $9600 to clear it?

(9) Find the amount to be paid if Charles borrowed a sum of $5900 at 7% simple interest for 8 years.

(10) Find the amount to be paid if Patricia borrowed a sum of $5150 at 6% simple interest for 8 years.