🏡 Home
    1. Time and Distance
    2. Time and Work
    3. Profit And Loss
    4. Average
    5. Percentage
    6. Simple Interest
    7. Questions based on ages
    1. Math
    2. Chemistry
    3. Chemistry Hindi
    4. Biology
    5. Exemplar Solution
    1. 11th physics
    2. 11th physics-hindi
    1. Science 10th (English)
    2. Science 10th (Hindi)
    3. Mathematics
    4. Math (Hindi)
    5. Social Science
    1. Science (English)
    2. 9th-Science (Hindi)
    1. 8th-Science (English)
    2. 8th-Science (Hindi)
    3. 8th-math (English)
    4. 8th-math (Hindi)
    1. 7th Math
    2. 7th Math(Hindi)
    1. Sixth Science
    2. 6th Science(hindi)
    1. Five Science
    1. Science (English)
    2. Science (Hindi)
    1. Std 10 science
    2. Std 4 science
    3. Std two EVS
    4. Std two Math
    5. MCQs Math
    6. एमoसीoक्यूo गणित
    7. Civil Service
    1. General Math (Hindi version)
    1. About Us
    2. Contact Us
10upon10.com

Simple Interest
Math MCQs


Question :  ( 1 of 10 )  Daniel took a loan of $6200 at the rate of 9% simple interest per annum. If he paid an amount of $11780 to clear the loan, then find the time period of the loan.

(A)  258.39 km
(B)  172.26 km
(C)  215.33 km
(D)  137.81 km
Your Selection   15

Correct Answer  10

Solution & Explanation

Solution

Given,

Principal (P) = $6200

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $11780

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $11780 – $6200 = $5580

Thus, Simple Interest = $5580

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 5580/6200 × 9

= 558000/55800

= 10 years (using formula)

Thus, Time (T) = 10 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $6200

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $5580 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $6200

= 9/100 × 6200

= 9 × 6200/100

= 55800/100 = 558

Thus, simple Interest for 1 year = $558

Now,

∵ If the simple Interest is $558, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/558 years

∴ If the simple Interest is $5580, then the time = 1/558 × 5580 years

= 1 × 5580/558 years

= 5580/558 = 10 years

Thus, time (T) = 10 years Answer


Similar Questions

(1) What amount will be due after 2 years if Christopher borrowed a sum of $3500 at a 8% simple interest?

(2) Calculate the amount due after 9 years if Michael borrowed a sum of $5300 at a rate of 2% simple interest.

(3) Calculate the amount due if Robert borrowed a sum of $3100 at 9% simple interest for 4 years.

(4) In how much time a principal of $3150 will amount to $3339 at a simple interest of 2% per annum?

(5) Find the amount to be paid if Sarah borrowed a sum of $5850 at 8% simple interest for 8 years.

(6) Calculate the amount due if Patricia borrowed a sum of $3150 at 8% simple interest for 3 years.

(7) What amount does Christopher have to pay after 6 years if he takes a loan of $4000 at 9% simple interest?

(8) Calculate the amount due if Richard borrowed a sum of $3600 at 5% simple interest for 3 years.

(9) What amount does Linda have to pay after 6 years if he takes a loan of $3350 at 4% simple interest?

(10) What amount does Linda have to pay after 6 years if he takes a loan of $3350 at 10% simple interest?