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Time and Work
Math MCQs


Question :    If James can finish the work in 24 days and John can finish the same work in 40 days, then in how many days both can finish the work together?


Correct Answer  15 days

Solution & Explanation

Solution

Given,

The number of days to finish the work by James = 24 days

And, the number of days to finish the same work by John = 40 days

Thus, the number of days to finish the work by James and John together = ?

Here,

∵ In 24 days the work done by James = 1

∴ In 1 day, the work done by James = 1/24 part

Similarly,

∵ In 40 days the work done by John = 1

∴ In 1 day, the work done by John = 1/40 part

Now, in 1 day, the work done by James and John together

= In 1 day work done by James + In 1 day the work done by John

= 1/24 + 1/40

= 5 + 3/120

= 8/120 part of work

= 8 ÷ 8/120 ÷ 8 part of work

= 1/15 part of work

This means, in 1 day, 1/15 part of the work is done by James and John together.

Now, the number of days required to finish 1/15 part of work by James + John working together = 1

∴ the number of days required to finish 1 work by James + John together

= 1/1/15

= 1 × 15/1 = 15/1 days

= 15 days

Thus, James and John working together will finish the work in 15 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, and B can finish the same work in b days,
then working together the number of days require to finish the work
= a × b/a + b days.

Here given,

The number of days required to finish the work by James = 24 days

And the number of days required to finish the same work by John = 40 days

Thus, the number of days required to finish the work James and John working together = ?

Here a = 24 days

And, b = 40 days

Thus, using formula a × b/a + b days

The number of days required to finish the work when James and John working together

= 24 × 40/24 + 40 days

= 960/64 days

= 960 ÷ 64/64 ÷ 64 = 15/1 days

= 15 days

Thus, James and John together will finish the work in 15 days Answer


Similar Questions

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