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Time and Work
Math MCQs


Question :    George can finish a work in 47 days. Timothy can finish the same work in 48 days while Ronald can finish the work in 49 days. How long will it take to finish it if they work together?


Correct Answer  15 6879/6911 days or 15.995 days

Solution & Explanation

Solution

Given,

The number of days required to finish a piece of work by George = 47 days

And, the number of days required to finish the same work by Timothy = 48 days

And, the number of days required to finish the same work by Ronald = 49 days

Thus, the number of days required to finish the work by all of them if they work together = ?

Here,

∵ In 47 days the work is done by George = 1

∴ The work done by George in 1 day = 1/47

Similarly,

∵ In 48 days the work is done by Timothy = 1

∴ The work done by Timothy in 1 day = 1/48

Similarly,

∵ In 49 days the work is done by Ronald = 1

∴ The work done by Ronald in 1 day = 1/49 part

Now, the work done by George, Timothy, and Ronald together in 1 day

= George's 1 day work + Timothy's 1 day work + Ronald's 1 day work

= 1/47 + 1/48 + 1/49

= 2352 + 2303 + 2256/110544

= 6911/110544 part of work

This means in 1 day, 6911/110544 part of work is done by George, Timothy and Ronald working together.

Now, the number of days required to finish 6911/110544 part of work by George, Timothy, and Ronald working together = 1

∴ the number of days required to finish the whole work (1 work) by George + Timothy + Ronald together

= 1/6911/110544

= 1 × 110544/6911 = 110544/6911 days

= 15 6879/6911 days = or 15.995 days

Thus, George, Timothy, and Ronald working together will finish the total work (1 work) in 15 6879/6911 days = or 15.995 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, B can finish the same work in b days, and C can finish the work in c days
then working together the number of days required to finish the work
= a × b × c/ab + ac + bc days.

Here given,

The number of days required to finish the work by George = 47 days

And the number of days required to finish the same work by Timothy = 48 days

And the number of days required to finish the work by Ronald = 49 days

Thus, the number of days required to finish the work by George, Timothy, and Ronald together = ?

Here a = 47 days

And, b = 48 days

And, c = 49 days

Thus, using formula a × b × c/ab + ac + bc days

The number of days required to finish the work when George, Timothy, and Ronald working together

= 47 × 48 × 49/47 × 48 + 47 × 49 + 48 × 49 days

= 110544/2256 + 2303 + 2352 days

= 110544/6911 days

= 110544/6911 days

= 15 6879/6911 days or 15.995

Thus, George, Timothy, and Ronald together will finish the work in 15 6879/6911 days or 15.995 days Answer


Similar Questions

(1) If Joshua can finish the work in 43 days and Benjamin can finish the same work in 48 days, then in how many days both can finish the work together?

(2) If A can do a piece of work in 2 days, B can do the same piece of work in 3 days, while C alone can do the same work in 4 days. Find the number of days to finish the work when they all will work together.

(3) If Nancy can finish the work in 25 days and Ronald can finish the same work in 28 days, then in how many days both can finish the work together?

(4) Karen can finish a work in 24 days. Nancy can finish the same work in 29 days while Betty can finish the work in 34 days. How long will it take to finish it if they work together?

(5) Michael can finish a work in 7 days. David can finish the same work in 8 days while William can finish the work in 9 days. How long will it take to finish it if they work together?

(6) If Linda can finish the work in 9 days and Charles can finish the same work in 13 days, then in how many days both can finish the work together?

(7) If Joshua can finish the work in 40 days and Benjamin can finish the same work in 44 days, then in how many days both can finish the work together?

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