Average
MCQs Math


Question:     Find the average of the first 2006 odd numbers.


Correct Answer  2006

Solution And Explanation

Explanation

Method to find the average

Step : (1) Find the sum of given numbers

Step: (2) Divide the sum of given number by the number of numbers. This will give the average of given numbers

The first 2006 odd numbers are

1, 3, 5, 7, 9, . . . . 2006 th terms

Calculation of the sum of the first 2006 odd numbers

We can find the sum of the first 2006 odd numbers by simply adding them, but this is a bit difficult. And if the list is long, it is very difficult to find their sum. So, in such a situation, we will use a formula to find the sum of given numbers that form a particular pattern.

Here, the list of the first 2006 odd numbers forms an Arithmetic series

In an Arithmetic Series, the common difference is the same. This means the difference between two consecutive terms are same in an Arithmetic Series.

The sum of n terms of an Arithmetic Series

Sn = n/2 [2a + (n – 1) d]

Where, n = number of terms, a = first term, and d = common difference

In the series of first 2006 odd number,

n = 2006, a = 1, and d = 2

Thus, sum of the first 2006 odd numbers

S2006 = 2006/2 [2 × 1 + (2006 – 1) 2]

= 2006/2 [2 + 2005 × 2]

= 2006/2 [2 + 4010]

= 2006/2 × 4012

= 2006/2 × 4012 2006

= 2006 × 2006 = 4024036

⇒ The sum of first 2006 odd numbers (Sn) = 4024036

Shortcut Method to find the sum of first n odd numbers

Thus, the sum of first n odd numbers = n2

Thus, the sum of first 2006 odd numbers

= 20062 = 4024036

⇒ The sum of first 2006 odd numbers = 4024036

Calculation of the Average of the first 2006 odd numbers

Formula to find the Average

Average = Sum of given numbers/Number of numbers

Thus, The average of the first 2006 odd numbers

= Sum of first 2006 odd numbers/2006

= 4024036/2006 = 2006

Thus, the average of the first 2006 odd numbers = 2006 Answer

Shortcut Trick to find the Average of the first n odd numbers

The average of the first 2 odd numbers

= 1 + 3/2

= 4/2 = 2

Thus, the average of the first 2 odd numbers = 2

The average of the first 3 odd numbers

= 1 + 3 + 5/3

= 9/3 = 3

Thus, the average of the first 3 odd numbers = 3

The average of the first 4 odd numbers

= 1 + 3 + 5 + 7/4

= 16/4 = 4

Thus, the average of the first 4 odd numbers = 4

The average of the first 5 odd numbers

= 1 + 3 + 5 + 7 + 9/5

= 25/5 = 5

Thus, the average of the first 5 odd numbers = 5

Thus, the Average of the the First n odd numbers = n

Thus, the average of the first 2006 odd numbers = 2006

Thus, the average of the first 2006 odd numbers = 2006 Answer


Similar Questions

(1) Find the average of odd numbers from 15 to 29

(2) What is the average of the first 1889 even numbers?

(3) What will be the average of the first 4090 odd numbers?

(4) Find the average of even numbers from 6 to 976

(5) Find the average of odd numbers from 3 to 447

(6) What is the average of the first 591 even numbers?

(7) Find the average of even numbers from 10 to 636

(8) Find the average of the first 3149 even numbers.

(9) Find the average of the first 2336 odd numbers.

(10) Find the average of even numbers from 4 to 118


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