Question:
What is the average of the first 1998 even numbers?
Correct Answer
1999
Solution And Explanation
Explanation
Method to find the average
Step : (1) Find the sum of given numbers
Step: (2) Divide the sum of given number by the number of numbers. This will give the average of the given numbers
The first 1998 even numbers are
2, 4, 6, 8, . . . . 1998 th terms
Calculation of the sum of the first 1998 even numbers
We can find the sum of the first 1998 even numbers by simply adding them, but this is a bit difficult. And if the list is long, it is very difficult to find their sum. So, in such a situation, we will use a formula to find the sum of given numbers that form a particular pattern.
Here, the list of the first 1998 even numbers forms an Arithmetic series
In an Arithmetic Series, the common difference is the same. This means the difference between two consecutive terms are same in an Arithmetic Series.
The sum of n terms of an Arithmetic Series
Sn = n/2 [2a + (n – 1) d]
Where, n = number of terms, a = first term, and d = common difference
In the series of the first 1998 even number,
n = 1998, a = 2, and d = 2
Thus, sum of the first 1998 even numbers
S1998 = 1998/2 [2 × 2 + (1998 – 1) 2]
= 1998/2 [4 + 1997 × 2]
= 1998/2 [4 + 3994]
= 1998/2 × 3998
= 1998/2 × 3998 1999
= 1998 × 1999 = 3994002
⇒ The sum of the first 1998 even numbers (S1998) = 3994002
Shortcut Method to find the sum of the first n even numbers
Thus, the sum of the first n even numbers = n2 + n
Thus, the sum of the first 1998 even numbers
= 19982 + 1998
= 3992004 + 1998 = 3994002
⇒ The sum of the first 1998 even numbers = 3994002
Calculation of the Average of the first 1998 even numbers
Formula to find the Average
Average = Sum of the given numbers/Number of the numbers
Thus, The average of the first 1998 even numbers
= Sum of the first 1998 even numbers/1998
= 3994002/1998 = 1999
Thus, the average of the first 1998 even numbers = 1999 Answer
Shortcut Trick to find the Average of the first n even numbers
(1) The average of the first 2 even numbers
= 2 + 4/2
= 6/2 = 3
Thus, the average of the first 2 even numbers = 3
(2) The average of the first 3 even numbers
= 2 + 4 + 6/3
= 12/3 = 4
Thus, the average of the first 3 even numbers = 4
(3) The average of the first 4 even numbers
= 2 + 4 + 6 + 8/4
= 20/4 = 5
Thus, the average of the first 4 even numbers = 5
(4) The average of the first 5 even numbers
= 2 + 4 + 6 + 8 + 10/5
= 30/5 = 6
Thus, the average of the first 5 even numbers = 6
Thus, the Average of the First n even numbers = n + 1
Thus, the average of the first 1998 even numbers = 1998 + 1 = 1999
Thus, the average of the first 1998 even numbers = 1999 Answer
Similar Questions
(1) Find the average of odd numbers from 7 to 383
(2) Find the average of even numbers from 8 to 116
(3) Find the average of the first 2663 even numbers.
(4) Find the average of the first 3522 even numbers.
(5) What will be the average of the first 4161 odd numbers?
(6) What will be the average of the first 4850 odd numbers?
(7) Find the average of odd numbers from 7 to 171
(8) Find the average of the first 2199 odd numbers.
(9) Find the average of odd numbers from 13 to 1495
(10) Find the average of odd numbers from 9 to 1409