Question:
Find the average of the first 4110 even numbers.
Correct Answer
4111
Solution And Explanation
Explanation
Method to find the average
Step : (1) Find the sum of given numbers
Step: (2) Divide the sum of given number by the number of numbers. This will give the average of the given numbers
The first 4110 even numbers are
2, 4, 6, 8, . . . . 4110 th terms
Calculation of the sum of the first 4110 even numbers
We can find the sum of the first 4110 even numbers by simply adding them, but this is a bit difficult. And if the list is long, it is very difficult to find their sum. So, in such a situation, we will use a formula to find the sum of given numbers that form a particular pattern.
Here, the list of the first 4110 even numbers forms an Arithmetic series
In an Arithmetic Series, the common difference is the same. This means the difference between two consecutive terms are same in an Arithmetic Series.
The sum of n terms of an Arithmetic Series
Sn = n/2 [2a + (n – 1) d]
Where, n = number of terms, a = first term, and d = common difference
In the series of the first 4110 even number,
n = 4110, a = 2, and d = 2
Thus, sum of the first 4110 even numbers
S4110 = 4110/2 [2 × 2 + (4110 – 1) 2]
= 4110/2 [4 + 4109 × 2]
= 4110/2 [4 + 8218]
= 4110/2 × 8222
= 4110/2 × 8222 4111
= 4110 × 4111 = 16896210
⇒ The sum of the first 4110 even numbers (S4110) = 16896210
Shortcut Method to find the sum of the first n even numbers
Thus, the sum of the first n even numbers = n2 + n
Thus, the sum of the first 4110 even numbers
= 41102 + 4110
= 16892100 + 4110 = 16896210
⇒ The sum of the first 4110 even numbers = 16896210
Calculation of the Average of the first 4110 even numbers
Formula to find the Average
Average = Sum of the given numbers/Number of the numbers
Thus, The average of the first 4110 even numbers
= Sum of the first 4110 even numbers/4110
= 16896210/4110 = 4111
Thus, the average of the first 4110 even numbers = 4111 Answer
Shortcut Trick to find the Average of the first n even numbers
(1) The average of the first 2 even numbers
= 2 + 4/2
= 6/2 = 3
Thus, the average of the first 2 even numbers = 3
(2) The average of the first 3 even numbers
= 2 + 4 + 6/3
= 12/3 = 4
Thus, the average of the first 3 even numbers = 4
(3) The average of the first 4 even numbers
= 2 + 4 + 6 + 8/4
= 20/4 = 5
Thus, the average of the first 4 even numbers = 5
(4) The average of the first 5 even numbers
= 2 + 4 + 6 + 8 + 10/5
= 30/5 = 6
Thus, the average of the first 5 even numbers = 6
Thus, the Average of the First n even numbers = n + 1
Thus, the average of the first 4110 even numbers = 4110 + 1 = 4111
Thus, the average of the first 4110 even numbers = 4111 Answer
Similar Questions
(1) Find the average of odd numbers from 11 to 879
(2) Find the average of odd numbers from 11 to 1207
(3) Find the average of the first 3606 even numbers.
(4) Find the average of even numbers from 8 to 1330
(5) Find the average of even numbers from 10 to 1992
(6) Find the average of even numbers from 10 to 1024
(7) Find the average of the first 3399 odd numbers.
(8) Find the average of odd numbers from 11 to 585
(9) Find the average of the first 4152 even numbers.
(10) What is the average of the first 410 even numbers?