Question:
Find the average of the first 4212 even numbers.
Correct Answer
4213
Solution And Explanation
Explanation
Method to find the average
Step : (1) Find the sum of given numbers
Step: (2) Divide the sum of given number by the number of numbers. This will give the average of the given numbers
The first 4212 even numbers are
2, 4, 6, 8, . . . . 4212 th terms
Calculation of the sum of the first 4212 even numbers
We can find the sum of the first 4212 even numbers by simply adding them, but this is a bit difficult. And if the list is long, it is very difficult to find their sum. So, in such a situation, we will use a formula to find the sum of given numbers that form a particular pattern.
Here, the list of the first 4212 even numbers forms an Arithmetic series
In an Arithmetic Series, the common difference is the same. This means the difference between two consecutive terms are same in an Arithmetic Series.
The sum of n terms of an Arithmetic Series
Sn = n/2 [2a + (n – 1) d]
Where, n = number of terms, a = first term, and d = common difference
In the series of the first 4212 even number,
n = 4212, a = 2, and d = 2
Thus, sum of the first 4212 even numbers
S4212 = 4212/2 [2 × 2 + (4212 – 1) 2]
= 4212/2 [4 + 4211 × 2]
= 4212/2 [4 + 8422]
= 4212/2 × 8426
= 4212/2 × 8426 4213
= 4212 × 4213 = 17745156
⇒ The sum of the first 4212 even numbers (S4212) = 17745156
Shortcut Method to find the sum of the first n even numbers
Thus, the sum of the first n even numbers = n2 + n
Thus, the sum of the first 4212 even numbers
= 42122 + 4212
= 17740944 + 4212 = 17745156
⇒ The sum of the first 4212 even numbers = 17745156
Calculation of the Average of the first 4212 even numbers
Formula to find the Average
Average = Sum of the given numbers/Number of the numbers
Thus, The average of the first 4212 even numbers
= Sum of the first 4212 even numbers/4212
= 17745156/4212 = 4213
Thus, the average of the first 4212 even numbers = 4213 Answer
Shortcut Trick to find the Average of the first n even numbers
(1) The average of the first 2 even numbers
= 2 + 4/2
= 6/2 = 3
Thus, the average of the first 2 even numbers = 3
(2) The average of the first 3 even numbers
= 2 + 4 + 6/3
= 12/3 = 4
Thus, the average of the first 3 even numbers = 4
(3) The average of the first 4 even numbers
= 2 + 4 + 6 + 8/4
= 20/4 = 5
Thus, the average of the first 4 even numbers = 5
(4) The average of the first 5 even numbers
= 2 + 4 + 6 + 8 + 10/5
= 30/5 = 6
Thus, the average of the first 5 even numbers = 6
Thus, the Average of the First n even numbers = n + 1
Thus, the average of the first 4212 even numbers = 4212 + 1 = 4213
Thus, the average of the first 4212 even numbers = 4213 Answer
Similar Questions
(1) Find the average of even numbers from 10 to 212
(2) Find the average of odd numbers from 13 to 643
(3) Find the average of even numbers from 12 to 850
(4) What is the average of the first 235 even numbers?
(5) Find the average of odd numbers from 11 to 501
(6) Find the average of even numbers from 4 to 770
(7) What is the average of the first 43 even numbers?
(8) Find the average of odd numbers from 11 to 469
(9) What will be the average of the first 4212 odd numbers?
(10) Find the average of the first 293 odd numbers.