Question:
Find the average of the first 4712 even numbers.
Correct Answer
4713
Solution And Explanation
Explanation
Method to find the average
Step : (1) Find the sum of given numbers
Step: (2) Divide the sum of given number by the number of numbers. This will give the average of the given numbers
The first 4712 even numbers are
2, 4, 6, 8, . . . . 4712 th terms
Calculation of the sum of the first 4712 even numbers
We can find the sum of the first 4712 even numbers by simply adding them, but this is a bit difficult. And if the list is long, it is very difficult to find their sum. So, in such a situation, we will use a formula to find the sum of given numbers that form a particular pattern.
Here, the list of the first 4712 even numbers forms an Arithmetic series
In an Arithmetic Series, the common difference is the same. This means the difference between two consecutive terms are same in an Arithmetic Series.
The sum of n terms of an Arithmetic Series
Sn = n/2 [2a + (n – 1) d]
Where, n = number of terms, a = first term, and d = common difference
In the series of the first 4712 even number,
n = 4712, a = 2, and d = 2
Thus, sum of the first 4712 even numbers
S4712 = 4712/2 [2 × 2 + (4712 – 1) 2]
= 4712/2 [4 + 4711 × 2]
= 4712/2 [4 + 9422]
= 4712/2 × 9426
= 4712/2 × 9426 4713
= 4712 × 4713 = 22207656
⇒ The sum of the first 4712 even numbers (S4712) = 22207656
Shortcut Method to find the sum of the first n even numbers
Thus, the sum of the first n even numbers = n2 + n
Thus, the sum of the first 4712 even numbers
= 47122 + 4712
= 22202944 + 4712 = 22207656
⇒ The sum of the first 4712 even numbers = 22207656
Calculation of the Average of the first 4712 even numbers
Formula to find the Average
Average = Sum of the given numbers/Number of the numbers
Thus, The average of the first 4712 even numbers
= Sum of the first 4712 even numbers/4712
= 22207656/4712 = 4713
Thus, the average of the first 4712 even numbers = 4713 Answer
Shortcut Trick to find the Average of the first n even numbers
(1) The average of the first 2 even numbers
= 2 + 4/2
= 6/2 = 3
Thus, the average of the first 2 even numbers = 3
(2) The average of the first 3 even numbers
= 2 + 4 + 6/3
= 12/3 = 4
Thus, the average of the first 3 even numbers = 4
(3) The average of the first 4 even numbers
= 2 + 4 + 6 + 8/4
= 20/4 = 5
Thus, the average of the first 4 even numbers = 5
(4) The average of the first 5 even numbers
= 2 + 4 + 6 + 8 + 10/5
= 30/5 = 6
Thus, the average of the first 5 even numbers = 6
Thus, the Average of the First n even numbers = n + 1
Thus, the average of the first 4712 even numbers = 4712 + 1 = 4713
Thus, the average of the first 4712 even numbers = 4713 Answer
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