Question:
Find the average of the first 4918 even numbers.
Correct Answer
4919
Solution And Explanation
Explanation
Method to find the average
Step : (1) Find the sum of given numbers
Step: (2) Divide the sum of given number by the number of numbers. This will give the average of the given numbers
The first 4918 even numbers are
2, 4, 6, 8, . . . . 4918 th terms
Calculation of the sum of the first 4918 even numbers
We can find the sum of the first 4918 even numbers by simply adding them, but this is a bit difficult. And if the list is long, it is very difficult to find their sum. So, in such a situation, we will use a formula to find the sum of given numbers that form a particular pattern.
Here, the list of the first 4918 even numbers forms an Arithmetic series
In an Arithmetic Series, the common difference is the same. This means the difference between two consecutive terms are same in an Arithmetic Series.
The sum of n terms of an Arithmetic Series
Sn = n/2 [2a + (n – 1) d]
Where, n = number of terms, a = first term, and d = common difference
In the series of the first 4918 even number,
n = 4918, a = 2, and d = 2
Thus, sum of the first 4918 even numbers
S4918 = 4918/2 [2 × 2 + (4918 – 1) 2]
= 4918/2 [4 + 4917 × 2]
= 4918/2 [4 + 9834]
= 4918/2 × 9838
= 4918/2 × 9838 4919
= 4918 × 4919 = 24191642
⇒ The sum of the first 4918 even numbers (S4918) = 24191642
Shortcut Method to find the sum of the first n even numbers
Thus, the sum of the first n even numbers = n2 + n
Thus, the sum of the first 4918 even numbers
= 49182 + 4918
= 24186724 + 4918 = 24191642
⇒ The sum of the first 4918 even numbers = 24191642
Calculation of the Average of the first 4918 even numbers
Formula to find the Average
Average = Sum of the given numbers/Number of the numbers
Thus, The average of the first 4918 even numbers
= Sum of the first 4918 even numbers/4918
= 24191642/4918 = 4919
Thus, the average of the first 4918 even numbers = 4919 Answer
Shortcut Trick to find the Average of the first n even numbers
(1) The average of the first 2 even numbers
= 2 + 4/2
= 6/2 = 3
Thus, the average of the first 2 even numbers = 3
(2) The average of the first 3 even numbers
= 2 + 4 + 6/3
= 12/3 = 4
Thus, the average of the first 3 even numbers = 4
(3) The average of the first 4 even numbers
= 2 + 4 + 6 + 8/4
= 20/4 = 5
Thus, the average of the first 4 even numbers = 5
(4) The average of the first 5 even numbers
= 2 + 4 + 6 + 8 + 10/5
= 30/5 = 6
Thus, the average of the first 5 even numbers = 6
Thus, the Average of the First n even numbers = n + 1
Thus, the average of the first 4918 even numbers = 4918 + 1 = 4919
Thus, the average of the first 4918 even numbers = 4919 Answer
Similar Questions
(1) What will be the average of the first 4702 odd numbers?
(2) Find the average of the first 2639 even numbers.
(3) Find the average of the first 318 odd numbers.
(4) Find the average of the first 3053 even numbers.
(5) Find the average of even numbers from 4 to 914
(6) Find the average of odd numbers from 7 to 1355
(7) Find the average of the first 2467 odd numbers.
(8) Find the average of odd numbers from 15 to 987
(9) Find the average of even numbers from 4 to 768
(10) Find the average of odd numbers from 7 to 385