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MCQs Math


Question:     Find the average of odd numbers from 5 to 1253


Correct Answer  629

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 5 to 1253

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 5 to 1253 are

5, 7, 9, . . . . 1253

After observing the above list of the odd numbers from 5 to 1253 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 5 to 1253 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 5 to 1253

The First Term (a) = 5

The Common Difference (d) = 2

And the last term (ℓ) = 1253

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 5 to 1253

= 5 + 1253/2

= 1258/2 = 629

Thus, the average of the odd numbers from 5 to 1253 = 629 Answer

Method (2) to find the average of the odd numbers from 5 to 1253

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 5 to 1253 are

5, 7, 9, . . . . 1253

The odd numbers from 5 to 1253 form an Arithmetic Series in which

The First Term (a) = 5

The Common Difference (d) = 2

And the last term (ℓ) = 1253

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 5 to 1253

1253 = 5 + (n – 1) × 2

⇒ 1253 = 5 + 2 n – 2

⇒ 1253 = 5 – 2 + 2 n

⇒ 1253 = 3 + 2 n

After transposing 3 to LHS

⇒ 1253 – 3 = 2 n

⇒ 1250 = 2 n

After rearranging the above expression

⇒ 2 n = 1250

After transposing 2 to RHS

⇒ n = 1250/2

⇒ n = 625

Thus, the number of terms of odd numbers from 5 to 1253 = 625

This means 1253 is the 625th term.

Finding the sum of the given odd numbers from 5 to 1253

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 5 to 1253

= 625/2 (5 + 1253)

= 625/2 × 1258

= 625 × 1258/2

= 786250/2 = 393125

Thus, the sum of all terms of the given odd numbers from 5 to 1253 = 393125

And, the total number of terms = 625

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 5 to 1253

= 393125/625 = 629

Thus, the average of the given odd numbers from 5 to 1253 = 629 Answer


Similar Questions

(1) Find the average of the first 2679 odd numbers.

(2) Find the average of even numbers from 10 to 1610

(3) Find the average of odd numbers from 11 to 381

(4) Find the average of even numbers from 6 to 1706

(5) Find the average of the first 3318 odd numbers.

(6) Find the average of the first 2352 even numbers.

(7) Find the average of the first 2210 odd numbers.

(8) Find the average of odd numbers from 7 to 589

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