Average
MCQs Math


Question:     Find the average of odd numbers from 5 to 1293


Correct Answer  649

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 5 to 1293

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 5 to 1293 are

5, 7, 9, . . . . 1293

After observing the above list of the odd numbers from 5 to 1293 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 5 to 1293 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 5 to 1293

The First Term (a) = 5

The Common Difference (d) = 2

And the last term (ℓ) = 1293

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 5 to 1293

= 5 + 1293/2

= 1298/2 = 649

Thus, the average of the odd numbers from 5 to 1293 = 649 Answer

Method (2) to find the average of the odd numbers from 5 to 1293

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 5 to 1293 are

5, 7, 9, . . . . 1293

The odd numbers from 5 to 1293 form an Arithmetic Series in which

The First Term (a) = 5

The Common Difference (d) = 2

And the last term (ℓ) = 1293

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 5 to 1293

1293 = 5 + (n – 1) × 2

⇒ 1293 = 5 + 2 n – 2

⇒ 1293 = 5 – 2 + 2 n

⇒ 1293 = 3 + 2 n

After transposing 3 to LHS

⇒ 1293 – 3 = 2 n

⇒ 1290 = 2 n

After rearranging the above expression

⇒ 2 n = 1290

After transposing 2 to RHS

⇒ n = 1290/2

⇒ n = 645

Thus, the number of terms of odd numbers from 5 to 1293 = 645

This means 1293 is the 645th term.

Finding the sum of the given odd numbers from 5 to 1293

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 5 to 1293

= 645/2 (5 + 1293)

= 645/2 × 1298

= 645 × 1298/2

= 837210/2 = 418605

Thus, the sum of all terms of the given odd numbers from 5 to 1293 = 418605

And, the total number of terms = 645

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 5 to 1293

= 418605/645 = 649

Thus, the average of the given odd numbers from 5 to 1293 = 649 Answer


Similar Questions

(1) Find the average of the first 2979 even numbers.

(2) Find the average of the first 2485 even numbers.

(3) Find the average of the first 224 odd numbers.

(4) Find the average of even numbers from 12 to 352

(5) Find the average of the first 2999 odd numbers.

(6) What is the average of the first 1196 even numbers?

(7) Find the average of even numbers from 10 to 1404

(8) Find the average of the first 4824 even numbers.

(9) Find the average of even numbers from 4 to 1208

(10) Find the average of the first 4692 even numbers.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©