Average
MCQs Math


Question:     Find the average of odd numbers from 5 to 1409


Correct Answer  707

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 5 to 1409

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 5 to 1409 are

5, 7, 9, . . . . 1409

After observing the above list of the odd numbers from 5 to 1409 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 5 to 1409 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 5 to 1409

The First Term (a) = 5

The Common Difference (d) = 2

And the last term (ℓ) = 1409

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 5 to 1409

= 5 + 1409/2

= 1414/2 = 707

Thus, the average of the odd numbers from 5 to 1409 = 707 Answer

Method (2) to find the average of the odd numbers from 5 to 1409

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 5 to 1409 are

5, 7, 9, . . . . 1409

The odd numbers from 5 to 1409 form an Arithmetic Series in which

The First Term (a) = 5

The Common Difference (d) = 2

And the last term (ℓ) = 1409

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 5 to 1409

1409 = 5 + (n – 1) × 2

⇒ 1409 = 5 + 2 n – 2

⇒ 1409 = 5 – 2 + 2 n

⇒ 1409 = 3 + 2 n

After transposing 3 to LHS

⇒ 1409 – 3 = 2 n

⇒ 1406 = 2 n

After rearranging the above expression

⇒ 2 n = 1406

After transposing 2 to RHS

⇒ n = 1406/2

⇒ n = 703

Thus, the number of terms of odd numbers from 5 to 1409 = 703

This means 1409 is the 703th term.

Finding the sum of the given odd numbers from 5 to 1409

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 5 to 1409

= 703/2 (5 + 1409)

= 703/2 × 1414

= 703 × 1414/2

= 994042/2 = 497021

Thus, the sum of all terms of the given odd numbers from 5 to 1409 = 497021

And, the total number of terms = 703

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 5 to 1409

= 497021/703 = 707

Thus, the average of the given odd numbers from 5 to 1409 = 707 Answer


Similar Questions

(1) Find the average of odd numbers from 9 to 695

(2) Find the average of even numbers from 4 to 764

(3) Find the average of odd numbers from 5 to 255

(4) Find the average of odd numbers from 7 to 225

(5) Find the average of the first 2056 even numbers.

(6) Find the average of the first 2439 even numbers.

(7) If the average of four consecutive even numbers is 39, then find the smallest and the greatest numbers among the given even numbers.

(8) What is the average of the first 1386 even numbers?

(9) Find the average of odd numbers from 13 to 133

(10) Find the average of even numbers from 8 to 210


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©