Question:
Find the average of odd numbers from 7 to 443
Correct Answer
225
Solution And Explanation
Solution
Method (1) to find the average of the odd numbers from 7 to 443
Shortcut Trick to find the average of the given continuous odd numbers
The odd numbers from 7 to 443 are
7, 9, 11, . . . . 443
After observing the above list of the odd numbers from 7 to 443 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 7 to 443 form an Arithmetic Series.
In the Arithmetic Series of the odd numbers from 7 to 443
The First Term (a) = 7
The Common Difference (d) = 2
And the last term (ℓ) = 443
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the odd numbers from 7 to 443
= 7 + 443/2
= 450/2 = 225
Thus, the average of the odd numbers from 7 to 443 = 225 Answer
Method (2) to find the average of the odd numbers from 7 to 443
Finding the average of given continuous odd numbers after finding their sum
The odd numbers from 7 to 443 are
7, 9, 11, . . . . 443
The odd numbers from 7 to 443 form an Arithmetic Series in which
The First Term (a) = 7
The Common Difference (d) = 2
And the last term (ℓ) = 443
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the odd numbers from 7 to 443
443 = 7 + (n – 1) × 2
⇒ 443 = 7 + 2 n – 2
⇒ 443 = 7 – 2 + 2 n
⇒ 443 = 5 + 2 n
After transposing 5 to LHS
⇒ 443 – 5 = 2 n
⇒ 438 = 2 n
After rearranging the above expression
⇒ 2 n = 438
After transposing 2 to RHS
⇒ n = 438/2
⇒ n = 219
Thus, the number of terms of odd numbers from 7 to 443 = 219
This means 443 is the 219th term.
Finding the sum of the given odd numbers from 7 to 443
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given odd numbers from 7 to 443
= 219/2 (7 + 443)
= 219/2 × 450
= 219 × 450/2
= 98550/2 = 49275
Thus, the sum of all terms of the given odd numbers from 7 to 443 = 49275
And, the total number of terms = 219
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given odd numbers from 7 to 443
= 49275/219 = 225
Thus, the average of the given odd numbers from 7 to 443 = 225 Answer
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