Average
MCQs Math


Question:     Find the average of odd numbers from 7 to 1103


Correct Answer  555

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 7 to 1103

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 7 to 1103 are

7, 9, 11, . . . . 1103

After observing the above list of the odd numbers from 7 to 1103 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 7 to 1103 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 7 to 1103

The First Term (a) = 7

The Common Difference (d) = 2

And the last term (ℓ) = 1103

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 7 to 1103

= 7 + 1103/2

= 1110/2 = 555

Thus, the average of the odd numbers from 7 to 1103 = 555 Answer

Method (2) to find the average of the odd numbers from 7 to 1103

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 7 to 1103 are

7, 9, 11, . . . . 1103

The odd numbers from 7 to 1103 form an Arithmetic Series in which

The First Term (a) = 7

The Common Difference (d) = 2

And the last term (ℓ) = 1103

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 7 to 1103

1103 = 7 + (n – 1) × 2

⇒ 1103 = 7 + 2 n – 2

⇒ 1103 = 7 – 2 + 2 n

⇒ 1103 = 5 + 2 n

After transposing 5 to LHS

⇒ 1103 – 5 = 2 n

⇒ 1098 = 2 n

After rearranging the above expression

⇒ 2 n = 1098

After transposing 2 to RHS

⇒ n = 1098/2

⇒ n = 549

Thus, the number of terms of odd numbers from 7 to 1103 = 549

This means 1103 is the 549th term.

Finding the sum of the given odd numbers from 7 to 1103

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 7 to 1103

= 549/2 (7 + 1103)

= 549/2 × 1110

= 549 × 1110/2

= 609390/2 = 304695

Thus, the sum of all terms of the given odd numbers from 7 to 1103 = 304695

And, the total number of terms = 549

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 7 to 1103

= 304695/549 = 555

Thus, the average of the given odd numbers from 7 to 1103 = 555 Answer


Similar Questions

(1) Find the average of the first 1878 odd numbers.

(2) Find the average of odd numbers from 3 to 1415

(3) Find the average of even numbers from 4 to 250

(4) Find the average of the first 2519 odd numbers.

(5) What will be the average of the first 4866 odd numbers?

(6) Find the average of odd numbers from 13 to 67

(7) Find the average of odd numbers from 3 to 1197

(8) What will be the average of the first 4085 odd numbers?

(9) Find the average of the first 2822 odd numbers.

(10) Find the average of even numbers from 6 to 930


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©