Question:
Find the average of odd numbers from 9 to 223
Correct Answer
116
Solution And Explanation
Solution
Method (1) to find the average of the odd numbers from 9 to 223
Shortcut Trick to find the average of the given continuous odd numbers
The odd numbers from 9 to 223 are
9, 11, 13, . . . . 223
After observing the above list of the odd numbers from 9 to 223 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 9 to 223 form an Arithmetic Series.
In the Arithmetic Series of the odd numbers from 9 to 223
The First Term (a) = 9
The Common Difference (d) = 2
And the last term (ℓ) = 223
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the odd numbers from 9 to 223
= 9 + 223/2
= 232/2 = 116
Thus, the average of the odd numbers from 9 to 223 = 116 Answer
Method (2) to find the average of the odd numbers from 9 to 223
Finding the average of given continuous odd numbers after finding their sum
The odd numbers from 9 to 223 are
9, 11, 13, . . . . 223
The odd numbers from 9 to 223 form an Arithmetic Series in which
The First Term (a) = 9
The Common Difference (d) = 2
And the last term (ℓ) = 223
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the odd numbers from 9 to 223
223 = 9 + (n – 1) × 2
⇒ 223 = 9 + 2 n – 2
⇒ 223 = 9 – 2 + 2 n
⇒ 223 = 7 + 2 n
After transposing 7 to LHS
⇒ 223 – 7 = 2 n
⇒ 216 = 2 n
After rearranging the above expression
⇒ 2 n = 216
After transposing 2 to RHS
⇒ n = 216/2
⇒ n = 108
Thus, the number of terms of odd numbers from 9 to 223 = 108
This means 223 is the 108th term.
Finding the sum of the given odd numbers from 9 to 223
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given odd numbers from 9 to 223
= 108/2 (9 + 223)
= 108/2 × 232
= 108 × 232/2
= 25056/2 = 12528
Thus, the sum of all terms of the given odd numbers from 9 to 223 = 12528
And, the total number of terms = 108
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given odd numbers from 9 to 223
= 12528/108 = 116
Thus, the average of the given odd numbers from 9 to 223 = 116 Answer
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