Question:
Find the average of odd numbers from 9 to 1203
Correct Answer
606
Solution And Explanation
Solution
Method (1) to find the average of the odd numbers from 9 to 1203
Shortcut Trick to find the average of the given continuous odd numbers
The odd numbers from 9 to 1203 are
9, 11, 13, . . . . 1203
After observing the above list of the odd numbers from 9 to 1203 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 9 to 1203 form an Arithmetic Series.
In the Arithmetic Series of the odd numbers from 9 to 1203
The First Term (a) = 9
The Common Difference (d) = 2
And the last term (ℓ) = 1203
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the odd numbers from 9 to 1203
= 9 + 1203/2
= 1212/2 = 606
Thus, the average of the odd numbers from 9 to 1203 = 606 Answer
Method (2) to find the average of the odd numbers from 9 to 1203
Finding the average of given continuous odd numbers after finding their sum
The odd numbers from 9 to 1203 are
9, 11, 13, . . . . 1203
The odd numbers from 9 to 1203 form an Arithmetic Series in which
The First Term (a) = 9
The Common Difference (d) = 2
And the last term (ℓ) = 1203
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the odd numbers from 9 to 1203
1203 = 9 + (n – 1) × 2
⇒ 1203 = 9 + 2 n – 2
⇒ 1203 = 9 – 2 + 2 n
⇒ 1203 = 7 + 2 n
After transposing 7 to LHS
⇒ 1203 – 7 = 2 n
⇒ 1196 = 2 n
After rearranging the above expression
⇒ 2 n = 1196
After transposing 2 to RHS
⇒ n = 1196/2
⇒ n = 598
Thus, the number of terms of odd numbers from 9 to 1203 = 598
This means 1203 is the 598th term.
Finding the sum of the given odd numbers from 9 to 1203
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given odd numbers from 9 to 1203
= 598/2 (9 + 1203)
= 598/2 × 1212
= 598 × 1212/2
= 724776/2 = 362388
Thus, the sum of all terms of the given odd numbers from 9 to 1203 = 362388
And, the total number of terms = 598
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given odd numbers from 9 to 1203
= 362388/598 = 606
Thus, the average of the given odd numbers from 9 to 1203 = 606 Answer
Similar Questions
(1) Find the average of the first 3962 even numbers.
(2) Find the average of odd numbers from 3 to 209
(3) Find the average of odd numbers from 9 to 1045
(4) Find the average of the first 2863 odd numbers.
(5) Find the average of even numbers from 12 to 1000
(6) Find the average of even numbers from 4 to 1502
(7) Find the average of even numbers from 6 to 684
(8) Find the average of odd numbers from 7 to 503
(9) What is the average of the first 551 even numbers?
(10) Find the average of even numbers from 10 to 918