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MCQs Math


Question:     Find the average of odd numbers from 9 to 1253


Correct Answer  631

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 9 to 1253

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 9 to 1253 are

9, 11, 13, . . . . 1253

After observing the above list of the odd numbers from 9 to 1253 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 9 to 1253 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 9 to 1253

The First Term (a) = 9

The Common Difference (d) = 2

And the last term (ℓ) = 1253

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 9 to 1253

= 9 + 1253/2

= 1262/2 = 631

Thus, the average of the odd numbers from 9 to 1253 = 631 Answer

Method (2) to find the average of the odd numbers from 9 to 1253

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 9 to 1253 are

9, 11, 13, . . . . 1253

The odd numbers from 9 to 1253 form an Arithmetic Series in which

The First Term (a) = 9

The Common Difference (d) = 2

And the last term (ℓ) = 1253

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 9 to 1253

1253 = 9 + (n – 1) × 2

⇒ 1253 = 9 + 2 n – 2

⇒ 1253 = 9 – 2 + 2 n

⇒ 1253 = 7 + 2 n

After transposing 7 to LHS

⇒ 1253 – 7 = 2 n

⇒ 1246 = 2 n

After rearranging the above expression

⇒ 2 n = 1246

After transposing 2 to RHS

⇒ n = 1246/2

⇒ n = 623

Thus, the number of terms of odd numbers from 9 to 1253 = 623

This means 1253 is the 623th term.

Finding the sum of the given odd numbers from 9 to 1253

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 9 to 1253

= 623/2 (9 + 1253)

= 623/2 × 1262

= 623 × 1262/2

= 786226/2 = 393113

Thus, the sum of all terms of the given odd numbers from 9 to 1253 = 393113

And, the total number of terms = 623

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 9 to 1253

= 393113/623 = 631

Thus, the average of the given odd numbers from 9 to 1253 = 631 Answer


Similar Questions

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(2) What will be the average of the first 4988 odd numbers?

(3) Find the average of the first 2032 odd numbers.

(4) What is the average of the first 1097 even numbers?

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(6) Find the average of the first 2274 odd numbers.

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