Average
MCQs Math


Question:     Find the average of odd numbers from 9 to 1501


Correct Answer  755

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 9 to 1501

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 9 to 1501 are

9, 11, 13, . . . . 1501

After observing the above list of the odd numbers from 9 to 1501 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 9 to 1501 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 9 to 1501

The First Term (a) = 9

The Common Difference (d) = 2

And the last term (ℓ) = 1501

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 9 to 1501

= 9 + 1501/2

= 1510/2 = 755

Thus, the average of the odd numbers from 9 to 1501 = 755 Answer

Method (2) to find the average of the odd numbers from 9 to 1501

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 9 to 1501 are

9, 11, 13, . . . . 1501

The odd numbers from 9 to 1501 form an Arithmetic Series in which

The First Term (a) = 9

The Common Difference (d) = 2

And the last term (ℓ) = 1501

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 9 to 1501

1501 = 9 + (n – 1) × 2

⇒ 1501 = 9 + 2 n – 2

⇒ 1501 = 9 – 2 + 2 n

⇒ 1501 = 7 + 2 n

After transposing 7 to LHS

⇒ 1501 – 7 = 2 n

⇒ 1494 = 2 n

After rearranging the above expression

⇒ 2 n = 1494

After transposing 2 to RHS

⇒ n = 1494/2

⇒ n = 747

Thus, the number of terms of odd numbers from 9 to 1501 = 747

This means 1501 is the 747th term.

Finding the sum of the given odd numbers from 9 to 1501

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 9 to 1501

= 747/2 (9 + 1501)

= 747/2 × 1510

= 747 × 1510/2

= 1127970/2 = 563985

Thus, the sum of all terms of the given odd numbers from 9 to 1501 = 563985

And, the total number of terms = 747

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 9 to 1501

= 563985/747 = 755

Thus, the average of the given odd numbers from 9 to 1501 = 755 Answer


Similar Questions

(1) Find the average of the first 2697 odd numbers.

(2) Find the average of the first 2047 odd numbers.

(3) Find the average of the first 2744 even numbers.

(4) Find the average of even numbers from 6 to 1818

(5) Find the average of odd numbers from 5 to 477

(6) What is the average of the first 1651 even numbers?

(7) Find the average of the first 3976 odd numbers.

(8) Find the average of the first 1667 odd numbers.

(9) Find the average of the first 1277 odd numbers.

(10) Find the average of even numbers from 8 to 1132


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©