Average
MCQs Math


Question:     Find the average of odd numbers from 11 to 661


Correct Answer  336

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 11 to 661

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 11 to 661 are

11, 13, 15, . . . . 661

After observing the above list of the odd numbers from 11 to 661 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 11 to 661 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 11 to 661

The First Term (a) = 11

The Common Difference (d) = 2

And the last term (ℓ) = 661

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 11 to 661

= 11 + 661/2

= 672/2 = 336

Thus, the average of the odd numbers from 11 to 661 = 336 Answer

Method (2) to find the average of the odd numbers from 11 to 661

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 11 to 661 are

11, 13, 15, . . . . 661

The odd numbers from 11 to 661 form an Arithmetic Series in which

The First Term (a) = 11

The Common Difference (d) = 2

And the last term (ℓ) = 661

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 11 to 661

661 = 11 + (n – 1) × 2

⇒ 661 = 11 + 2 n – 2

⇒ 661 = 11 – 2 + 2 n

⇒ 661 = 9 + 2 n

After transposing 9 to LHS

⇒ 661 – 9 = 2 n

⇒ 652 = 2 n

After rearranging the above expression

⇒ 2 n = 652

After transposing 2 to RHS

⇒ n = 652/2

⇒ n = 326

Thus, the number of terms of odd numbers from 11 to 661 = 326

This means 661 is the 326th term.

Finding the sum of the given odd numbers from 11 to 661

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 11 to 661

= 326/2 (11 + 661)

= 326/2 × 672

= 326 × 672/2

= 219072/2 = 109536

Thus, the sum of all terms of the given odd numbers from 11 to 661 = 109536

And, the total number of terms = 326

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 11 to 661

= 109536/326 = 336

Thus, the average of the given odd numbers from 11 to 661 = 336 Answer


Similar Questions

(1) Find the average of the first 2885 odd numbers.

(2) Find the average of even numbers from 6 to 1472

(3) Find the average of the first 2495 odd numbers.

(4) What is the average of the first 656 even numbers?

(5) Find the average of even numbers from 8 to 770

(6) What is the average of the first 1976 even numbers?

(7) Find the average of the first 569 odd numbers.

(8) Find the average of even numbers from 4 to 400

(9) Find the average of the first 3442 odd numbers.

(10) Find the average of the first 4074 even numbers.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©