Question:
Find the average of odd numbers from 11 to 803
Correct Answer
407
Solution And Explanation
Solution
Method (1) to find the average of the odd numbers from 11 to 803
Shortcut Trick to find the average of the given continuous odd numbers
The odd numbers from 11 to 803 are
11, 13, 15, . . . . 803
After observing the above list of the odd numbers from 11 to 803 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 11 to 803 form an Arithmetic Series.
In the Arithmetic Series of the odd numbers from 11 to 803
The First Term (a) = 11
The Common Difference (d) = 2
And the last term (ℓ) = 803
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the odd numbers from 11 to 803
= 11 + 803/2
= 814/2 = 407
Thus, the average of the odd numbers from 11 to 803 = 407 Answer
Method (2) to find the average of the odd numbers from 11 to 803
Finding the average of given continuous odd numbers after finding their sum
The odd numbers from 11 to 803 are
11, 13, 15, . . . . 803
The odd numbers from 11 to 803 form an Arithmetic Series in which
The First Term (a) = 11
The Common Difference (d) = 2
And the last term (ℓ) = 803
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the odd numbers from 11 to 803
803 = 11 + (n – 1) × 2
⇒ 803 = 11 + 2 n – 2
⇒ 803 = 11 – 2 + 2 n
⇒ 803 = 9 + 2 n
After transposing 9 to LHS
⇒ 803 – 9 = 2 n
⇒ 794 = 2 n
After rearranging the above expression
⇒ 2 n = 794
After transposing 2 to RHS
⇒ n = 794/2
⇒ n = 397
Thus, the number of terms of odd numbers from 11 to 803 = 397
This means 803 is the 397th term.
Finding the sum of the given odd numbers from 11 to 803
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given odd numbers from 11 to 803
= 397/2 (11 + 803)
= 397/2 × 814
= 397 × 814/2
= 323158/2 = 161579
Thus, the sum of all terms of the given odd numbers from 11 to 803 = 161579
And, the total number of terms = 397
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given odd numbers from 11 to 803
= 161579/397 = 407
Thus, the average of the given odd numbers from 11 to 803 = 407 Answer
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