Average
MCQs Math


Question:     Find the average of odd numbers from 15 to 117


Correct Answer  66

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 15 to 117

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 15 to 117 are

15, 17, 19, . . . . 117

After observing the above list of the odd numbers from 15 to 117 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 15 to 117 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 15 to 117

The First Term (a) = 15

The Common Difference (d) = 2

And the last term (ℓ) = 117

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 15 to 117

= 15 + 117/2

= 132/2 = 66

Thus, the average of the odd numbers from 15 to 117 = 66 Answer

Method (2) to find the average of the odd numbers from 15 to 117

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 15 to 117 are

15, 17, 19, . . . . 117

The odd numbers from 15 to 117 form an Arithmetic Series in which

The First Term (a) = 15

The Common Difference (d) = 2

And the last term (ℓ) = 117

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 15 to 117

117 = 15 + (n – 1) × 2

⇒ 117 = 15 + 2 n – 2

⇒ 117 = 15 – 2 + 2 n

⇒ 117 = 13 + 2 n

After transposing 13 to LHS

⇒ 117 – 13 = 2 n

⇒ 104 = 2 n

After rearranging the above expression

⇒ 2 n = 104

After transposing 2 to RHS

⇒ n = 104/2

⇒ n = 52

Thus, the number of terms of odd numbers from 15 to 117 = 52

This means 117 is the 52th term.

Finding the sum of the given odd numbers from 15 to 117

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 15 to 117

= 52/2 (15 + 117)

= 52/2 × 132

= 52 × 132/2

= 6864/2 = 3432

Thus, the sum of all terms of the given odd numbers from 15 to 117 = 3432

And, the total number of terms = 52

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 15 to 117

= 3432/52 = 66

Thus, the average of the given odd numbers from 15 to 117 = 66 Answer


Similar Questions

(1) Find the average of the first 2133 odd numbers.

(2) Find the average of the first 3063 even numbers.

(3) What will be the average of the first 4862 odd numbers?

(4) Find the average of the first 837 odd numbers.

(5) Find the average of even numbers from 4 to 1924

(6) Find the average of the first 4573 even numbers.

(7) Find the average of the first 4128 even numbers.

(8) Find the average of even numbers from 6 to 1188

(9) Find the average of the first 2231 even numbers.

(10) Find the average of even numbers from 4 to 454


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©