Average
MCQs Math


Question:     Find the average of odd numbers from 15 to 895


Correct Answer  455

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 15 to 895

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 15 to 895 are

15, 17, 19, . . . . 895

After observing the above list of the odd numbers from 15 to 895 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 15 to 895 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 15 to 895

The First Term (a) = 15

The Common Difference (d) = 2

And the last term (ℓ) = 895

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 15 to 895

= 15 + 895/2

= 910/2 = 455

Thus, the average of the odd numbers from 15 to 895 = 455 Answer

Method (2) to find the average of the odd numbers from 15 to 895

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 15 to 895 are

15, 17, 19, . . . . 895

The odd numbers from 15 to 895 form an Arithmetic Series in which

The First Term (a) = 15

The Common Difference (d) = 2

And the last term (ℓ) = 895

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 15 to 895

895 = 15 + (n – 1) × 2

⇒ 895 = 15 + 2 n – 2

⇒ 895 = 15 – 2 + 2 n

⇒ 895 = 13 + 2 n

After transposing 13 to LHS

⇒ 895 – 13 = 2 n

⇒ 882 = 2 n

After rearranging the above expression

⇒ 2 n = 882

After transposing 2 to RHS

⇒ n = 882/2

⇒ n = 441

Thus, the number of terms of odd numbers from 15 to 895 = 441

This means 895 is the 441th term.

Finding the sum of the given odd numbers from 15 to 895

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 15 to 895

= 441/2 (15 + 895)

= 441/2 × 910

= 441 × 910/2

= 401310/2 = 200655

Thus, the sum of all terms of the given odd numbers from 15 to 895 = 200655

And, the total number of terms = 441

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 15 to 895

= 200655/441 = 455

Thus, the average of the given odd numbers from 15 to 895 = 455 Answer


Similar Questions

(1) What will be the average of the first 4299 odd numbers?

(2) Find the average of the first 1887 odd numbers.

(3) What is the average of the first 1511 even numbers?

(4) What is the average of the first 1838 even numbers?

(5) Find the average of odd numbers from 9 to 251

(6) Find the average of the first 2957 even numbers.

(7) Find the average of the first 885 odd numbers.

(8) Find the average of odd numbers from 13 to 1095

(9) Find the average of the first 4748 even numbers.

(10) Find the average of the first 513 odd numbers.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©