Average
MCQs Math


Question:     Find the average of odd numbers from 15 to 1201


Correct Answer  608

Solution And Explanation

Solution

Method (1) to find the average of the odd numbers from 15 to 1201

Shortcut Trick to find the average of the given continuous odd numbers

The odd numbers from 15 to 1201 are

15, 17, 19, . . . . 1201

After observing the above list of the odd numbers from 15 to 1201 we find that the difference between two consecutive terms are equal. This means the list of the odd numbers from 15 to 1201 form an Arithmetic Series.

In the Arithmetic Series of the odd numbers from 15 to 1201

The First Term (a) = 15

The Common Difference (d) = 2

And the last term (ℓ) = 1201

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the odd numbers from 15 to 1201

= 15 + 1201/2

= 1216/2 = 608

Thus, the average of the odd numbers from 15 to 1201 = 608 Answer

Method (2) to find the average of the odd numbers from 15 to 1201

Finding the average of given continuous odd numbers after finding their sum

The odd numbers from 15 to 1201 are

15, 17, 19, . . . . 1201

The odd numbers from 15 to 1201 form an Arithmetic Series in which

The First Term (a) = 15

The Common Difference (d) = 2

And the last term (ℓ) = 1201

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the odd numbers from 15 to 1201

1201 = 15 + (n – 1) × 2

⇒ 1201 = 15 + 2 n – 2

⇒ 1201 = 15 – 2 + 2 n

⇒ 1201 = 13 + 2 n

After transposing 13 to LHS

⇒ 1201 – 13 = 2 n

⇒ 1188 = 2 n

After rearranging the above expression

⇒ 2 n = 1188

After transposing 2 to RHS

⇒ n = 1188/2

⇒ n = 594

Thus, the number of terms of odd numbers from 15 to 1201 = 594

This means 1201 is the 594th term.

Finding the sum of the given odd numbers from 15 to 1201

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given odd numbers from 15 to 1201

= 594/2 (15 + 1201)

= 594/2 × 1216

= 594 × 1216/2

= 722304/2 = 361152

Thus, the sum of all terms of the given odd numbers from 15 to 1201 = 361152

And, the total number of terms = 594

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given odd numbers from 15 to 1201

= 361152/594 = 608

Thus, the average of the given odd numbers from 15 to 1201 = 608 Answer


Similar Questions

(1) Find the average of odd numbers from 15 to 883

(2) What is the average of the first 328 even numbers?

(3) Find the average of the first 4001 even numbers.

(4) What is the average of the first 1247 even numbers?

(5) Find the average of even numbers from 6 to 54

(6) Find the average of even numbers from 12 to 1934

(7) Find the average of the first 2081 odd numbers.

(8) What will be the average of the first 4243 odd numbers?

(9) Find the average of even numbers from 8 to 1190

(10) Find the average of the first 3712 odd numbers.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©