Question:
Find the average of even numbers from 6 to 206
Correct Answer
106
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 206
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 206 are
6, 8, 10, . . . . 206
After observing the above list of the even numbers from 6 to 206 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 206 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 206
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 206
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 206
= 6 + 206/2
= 212/2 = 106
Thus, the average of the even numbers from 6 to 206 = 106 Answer
Method (2) to find the average of the even numbers from 6 to 206
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 206 are
6, 8, 10, . . . . 206
The even numbers from 6 to 206 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 206
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 206
206 = 6 + (n – 1) × 2
⇒ 206 = 6 + 2 n – 2
⇒ 206 = 6 – 2 + 2 n
⇒ 206 = 4 + 2 n
After transposing 4 to LHS
⇒ 206 – 4 = 2 n
⇒ 202 = 2 n
After rearranging the above expression
⇒ 2 n = 202
After transposing 2 to RHS
⇒ n = 202/2
⇒ n = 101
Thus, the number of terms of even numbers from 6 to 206 = 101
This means 206 is the 101th term.
Finding the sum of the given even numbers from 6 to 206
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 206
= 101/2 (6 + 206)
= 101/2 × 212
= 101 × 212/2
= 21412/2 = 10706
Thus, the sum of all terms of the given even numbers from 6 to 206 = 10706
And, the total number of terms = 101
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 206
= 10706/101 = 106
Thus, the average of the given even numbers from 6 to 206 = 106 Answer
Similar Questions
(1) Find the average of the first 296 odd numbers.
(2) What will be the average of the first 4966 odd numbers?
(3) Find the average of the first 2198 even numbers.
(4) Find the average of even numbers from 10 to 1736
(5) Find the average of odd numbers from 11 to 325
(6) What is the average of the first 37 odd numbers?
(7) Find the average of the first 4584 even numbers.
(8) Find the average of the first 1832 odd numbers.
(9) Find the average of odd numbers from 9 to 1023
(10) Find the average of the first 668 odd numbers.