Question:
Find the average of even numbers from 6 to 252
Correct Answer
129
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 252
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 252 are
6, 8, 10, . . . . 252
After observing the above list of the even numbers from 6 to 252 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 252 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 252
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 252
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 252
= 6 + 252/2
= 258/2 = 129
Thus, the average of the even numbers from 6 to 252 = 129 Answer
Method (2) to find the average of the even numbers from 6 to 252
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 252 are
6, 8, 10, . . . . 252
The even numbers from 6 to 252 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 252
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 252
252 = 6 + (n – 1) × 2
⇒ 252 = 6 + 2 n – 2
⇒ 252 = 6 – 2 + 2 n
⇒ 252 = 4 + 2 n
After transposing 4 to LHS
⇒ 252 – 4 = 2 n
⇒ 248 = 2 n
After rearranging the above expression
⇒ 2 n = 248
After transposing 2 to RHS
⇒ n = 248/2
⇒ n = 124
Thus, the number of terms of even numbers from 6 to 252 = 124
This means 252 is the 124th term.
Finding the sum of the given even numbers from 6 to 252
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 252
= 124/2 (6 + 252)
= 124/2 × 258
= 124 × 258/2
= 31992/2 = 15996
Thus, the sum of all terms of the given even numbers from 6 to 252 = 15996
And, the total number of terms = 124
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 252
= 15996/124 = 129
Thus, the average of the given even numbers from 6 to 252 = 129 Answer
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