Question:
Find the average of even numbers from 6 to 490
Correct Answer
248
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 490
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 490 are
6, 8, 10, . . . . 490
After observing the above list of the even numbers from 6 to 490 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 490 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 490
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 490
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 490
= 6 + 490/2
= 496/2 = 248
Thus, the average of the even numbers from 6 to 490 = 248 Answer
Method (2) to find the average of the even numbers from 6 to 490
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 490 are
6, 8, 10, . . . . 490
The even numbers from 6 to 490 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 490
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 490
490 = 6 + (n – 1) × 2
⇒ 490 = 6 + 2 n – 2
⇒ 490 = 6 – 2 + 2 n
⇒ 490 = 4 + 2 n
After transposing 4 to LHS
⇒ 490 – 4 = 2 n
⇒ 486 = 2 n
After rearranging the above expression
⇒ 2 n = 486
After transposing 2 to RHS
⇒ n = 486/2
⇒ n = 243
Thus, the number of terms of even numbers from 6 to 490 = 243
This means 490 is the 243th term.
Finding the sum of the given even numbers from 6 to 490
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 490
= 243/2 (6 + 490)
= 243/2 × 496
= 243 × 496/2
= 120528/2 = 60264
Thus, the sum of all terms of the given even numbers from 6 to 490 = 60264
And, the total number of terms = 243
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 490
= 60264/243 = 248
Thus, the average of the given even numbers from 6 to 490 = 248 Answer
Similar Questions
(1) Find the average of odd numbers from 13 to 153
(2) Find the average of odd numbers from 9 to 1097
(3) Find the average of odd numbers from 15 to 1389
(4) Find the average of odd numbers from 15 to 461
(5) Find the average of even numbers from 8 to 1346
(6) Find the average of even numbers from 6 to 266
(7) Find the average of even numbers from 6 to 1978
(8) Find the average of odd numbers from 11 to 1405
(9) Find the average of odd numbers from 5 to 1383
(10) Find the average of odd numbers from 5 to 1255