Average
MCQs Math


Question:     Find the average of even numbers from 6 to 728


Correct Answer  367

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 6 to 728

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 6 to 728 are

6, 8, 10, . . . . 728

After observing the above list of the even numbers from 6 to 728 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 728 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 6 to 728

The First Term (a) = 6

The Common Difference (d) = 2

And the last term (ℓ) = 728

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 6 to 728

= 6 + 728/2

= 734/2 = 367

Thus, the average of the even numbers from 6 to 728 = 367 Answer

Method (2) to find the average of the even numbers from 6 to 728

Finding the average of given continuous even numbers after finding their sum

The even numbers from 6 to 728 are

6, 8, 10, . . . . 728

The even numbers from 6 to 728 form an Arithmetic Series in which

The First Term (a) = 6

The Common Difference (d) = 2

And the last term (ℓ) = 728

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 6 to 728

728 = 6 + (n – 1) × 2

⇒ 728 = 6 + 2 n – 2

⇒ 728 = 6 – 2 + 2 n

⇒ 728 = 4 + 2 n

After transposing 4 to LHS

⇒ 728 – 4 = 2 n

⇒ 724 = 2 n

After rearranging the above expression

⇒ 2 n = 724

After transposing 2 to RHS

⇒ n = 724/2

⇒ n = 362

Thus, the number of terms of even numbers from 6 to 728 = 362

This means 728 is the 362th term.

Finding the sum of the given even numbers from 6 to 728

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 6 to 728

= 362/2 (6 + 728)

= 362/2 × 734

= 362 × 734/2

= 265708/2 = 132854

Thus, the sum of all terms of the given even numbers from 6 to 728 = 132854

And, the total number of terms = 362

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 6 to 728

= 132854/362 = 367

Thus, the average of the given even numbers from 6 to 728 = 367 Answer


Similar Questions

(1) Find the average of the first 1865 odd numbers.

(2) Find the average of the first 2339 odd numbers.

(3) Find the average of the first 3179 even numbers.

(4) What will be the average of the first 4869 odd numbers?

(5) Find the average of odd numbers from 5 to 895

(6) Find the average of the first 1498 odd numbers.

(7) Find the average of the first 2398 even numbers.

(8) Find the average of odd numbers from 5 to 1205

(9) Find the average of the first 3218 odd numbers.

(10) Find the average of odd numbers from 5 to 883


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©