Question:
Find the average of even numbers from 6 to 808
Correct Answer
407
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 808
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 808 are
6, 8, 10, . . . . 808
After observing the above list of the even numbers from 6 to 808 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 808 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 808
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 808
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 808
= 6 + 808/2
= 814/2 = 407
Thus, the average of the even numbers from 6 to 808 = 407 Answer
Method (2) to find the average of the even numbers from 6 to 808
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 808 are
6, 8, 10, . . . . 808
The even numbers from 6 to 808 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 808
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 808
808 = 6 + (n – 1) × 2
⇒ 808 = 6 + 2 n – 2
⇒ 808 = 6 – 2 + 2 n
⇒ 808 = 4 + 2 n
After transposing 4 to LHS
⇒ 808 – 4 = 2 n
⇒ 804 = 2 n
After rearranging the above expression
⇒ 2 n = 804
After transposing 2 to RHS
⇒ n = 804/2
⇒ n = 402
Thus, the number of terms of even numbers from 6 to 808 = 402
This means 808 is the 402th term.
Finding the sum of the given even numbers from 6 to 808
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 808
= 402/2 (6 + 808)
= 402/2 × 814
= 402 × 814/2
= 327228/2 = 163614
Thus, the sum of all terms of the given even numbers from 6 to 808 = 163614
And, the total number of terms = 402
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 808
= 163614/402 = 407
Thus, the average of the given even numbers from 6 to 808 = 407 Answer
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