Question:
Find the average of even numbers from 6 to 1062
Correct Answer
534
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 1062
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 1062 are
6, 8, 10, . . . . 1062
After observing the above list of the even numbers from 6 to 1062 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 1062 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 1062
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1062
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 1062
= 6 + 1062/2
= 1068/2 = 534
Thus, the average of the even numbers from 6 to 1062 = 534 Answer
Method (2) to find the average of the even numbers from 6 to 1062
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 1062 are
6, 8, 10, . . . . 1062
The even numbers from 6 to 1062 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1062
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 1062
1062 = 6 + (n – 1) × 2
⇒ 1062 = 6 + 2 n – 2
⇒ 1062 = 6 – 2 + 2 n
⇒ 1062 = 4 + 2 n
After transposing 4 to LHS
⇒ 1062 – 4 = 2 n
⇒ 1058 = 2 n
After rearranging the above expression
⇒ 2 n = 1058
After transposing 2 to RHS
⇒ n = 1058/2
⇒ n = 529
Thus, the number of terms of even numbers from 6 to 1062 = 529
This means 1062 is the 529th term.
Finding the sum of the given even numbers from 6 to 1062
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 1062
= 529/2 (6 + 1062)
= 529/2 × 1068
= 529 × 1068/2
= 564972/2 = 282486
Thus, the sum of all terms of the given even numbers from 6 to 1062 = 282486
And, the total number of terms = 529
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 1062
= 282486/529 = 534
Thus, the average of the given even numbers from 6 to 1062 = 534 Answer
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