Question:
Find the average of even numbers from 6 to 1256
Correct Answer
631
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 1256
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 1256 are
6, 8, 10, . . . . 1256
After observing the above list of the even numbers from 6 to 1256 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 1256 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 1256
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1256
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 1256
= 6 + 1256/2
= 1262/2 = 631
Thus, the average of the even numbers from 6 to 1256 = 631 Answer
Method (2) to find the average of the even numbers from 6 to 1256
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 1256 are
6, 8, 10, . . . . 1256
The even numbers from 6 to 1256 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1256
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 1256
1256 = 6 + (n – 1) × 2
⇒ 1256 = 6 + 2 n – 2
⇒ 1256 = 6 – 2 + 2 n
⇒ 1256 = 4 + 2 n
After transposing 4 to LHS
⇒ 1256 – 4 = 2 n
⇒ 1252 = 2 n
After rearranging the above expression
⇒ 2 n = 1252
After transposing 2 to RHS
⇒ n = 1252/2
⇒ n = 626
Thus, the number of terms of even numbers from 6 to 1256 = 626
This means 1256 is the 626th term.
Finding the sum of the given even numbers from 6 to 1256
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 1256
= 626/2 (6 + 1256)
= 626/2 × 1262
= 626 × 1262/2
= 790012/2 = 395006
Thus, the sum of all terms of the given even numbers from 6 to 1256 = 395006
And, the total number of terms = 626
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 1256
= 395006/626 = 631
Thus, the average of the given even numbers from 6 to 1256 = 631 Answer
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