Question:
Find the average of even numbers from 6 to 1340
Correct Answer
673
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 1340
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 1340 are
6, 8, 10, . . . . 1340
After observing the above list of the even numbers from 6 to 1340 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 1340 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 1340
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1340
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 1340
= 6 + 1340/2
= 1346/2 = 673
Thus, the average of the even numbers from 6 to 1340 = 673 Answer
Method (2) to find the average of the even numbers from 6 to 1340
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 1340 are
6, 8, 10, . . . . 1340
The even numbers from 6 to 1340 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1340
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 1340
1340 = 6 + (n – 1) × 2
⇒ 1340 = 6 + 2 n – 2
⇒ 1340 = 6 – 2 + 2 n
⇒ 1340 = 4 + 2 n
After transposing 4 to LHS
⇒ 1340 – 4 = 2 n
⇒ 1336 = 2 n
After rearranging the above expression
⇒ 2 n = 1336
After transposing 2 to RHS
⇒ n = 1336/2
⇒ n = 668
Thus, the number of terms of even numbers from 6 to 1340 = 668
This means 1340 is the 668th term.
Finding the sum of the given even numbers from 6 to 1340
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 1340
= 668/2 (6 + 1340)
= 668/2 × 1346
= 668 × 1346/2
= 899128/2 = 449564
Thus, the sum of all terms of the given even numbers from 6 to 1340 = 449564
And, the total number of terms = 668
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 1340
= 449564/668 = 673
Thus, the average of the given even numbers from 6 to 1340 = 673 Answer
Similar Questions
(1) Find the average of even numbers from 10 to 650
(2) Find the average of even numbers from 12 to 728
(3) Find the average of even numbers from 10 to 900
(4) Find the average of the first 823 odd numbers.
(5) What will be the average of the first 4341 odd numbers?
(6) Find the average of odd numbers from 5 to 185
(7) Find the average of odd numbers from 15 to 1337
(8) Find the average of the first 2885 even numbers.
(9) Find the average of odd numbers from 13 to 393
(10) Find the average of the first 2816 even numbers.