Question:
Find the average of even numbers from 6 to 1498
Correct Answer
752
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 1498
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 1498 are
6, 8, 10, . . . . 1498
After observing the above list of the even numbers from 6 to 1498 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 1498 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 1498
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1498
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 1498
= 6 + 1498/2
= 1504/2 = 752
Thus, the average of the even numbers from 6 to 1498 = 752 Answer
Method (2) to find the average of the even numbers from 6 to 1498
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 1498 are
6, 8, 10, . . . . 1498
The even numbers from 6 to 1498 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1498
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 1498
1498 = 6 + (n – 1) × 2
⇒ 1498 = 6 + 2 n – 2
⇒ 1498 = 6 – 2 + 2 n
⇒ 1498 = 4 + 2 n
After transposing 4 to LHS
⇒ 1498 – 4 = 2 n
⇒ 1494 = 2 n
After rearranging the above expression
⇒ 2 n = 1494
After transposing 2 to RHS
⇒ n = 1494/2
⇒ n = 747
Thus, the number of terms of even numbers from 6 to 1498 = 747
This means 1498 is the 747th term.
Finding the sum of the given even numbers from 6 to 1498
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 1498
= 747/2 (6 + 1498)
= 747/2 × 1504
= 747 × 1504/2
= 1123488/2 = 561744
Thus, the sum of all terms of the given even numbers from 6 to 1498 = 561744
And, the total number of terms = 747
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 1498
= 561744/747 = 752
Thus, the average of the given even numbers from 6 to 1498 = 752 Answer
Similar Questions
(1) Find the average of the first 4819 even numbers.
(2) Find the average of the first 3398 odd numbers.
(3) What is the average of the first 783 even numbers?
(4) Find the average of the first 2649 odd numbers.
(5) Find the average of odd numbers from 13 to 193
(6) Find the average of the first 2180 even numbers.
(7) Find the average of odd numbers from 3 to 701
(8) What will be the average of the first 4428 odd numbers?
(9) What is the average of the first 1753 even numbers?
(10) Find the average of the first 2511 even numbers.