Question:
Find the average of even numbers from 6 to 1500
Correct Answer
753
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 1500
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 1500 are
6, 8, 10, . . . . 1500
After observing the above list of the even numbers from 6 to 1500 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 1500 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 1500
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1500
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 1500
= 6 + 1500/2
= 1506/2 = 753
Thus, the average of the even numbers from 6 to 1500 = 753 Answer
Method (2) to find the average of the even numbers from 6 to 1500
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 1500 are
6, 8, 10, . . . . 1500
The even numbers from 6 to 1500 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1500
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 1500
1500 = 6 + (n – 1) × 2
⇒ 1500 = 6 + 2 n – 2
⇒ 1500 = 6 – 2 + 2 n
⇒ 1500 = 4 + 2 n
After transposing 4 to LHS
⇒ 1500 – 4 = 2 n
⇒ 1496 = 2 n
After rearranging the above expression
⇒ 2 n = 1496
After transposing 2 to RHS
⇒ n = 1496/2
⇒ n = 748
Thus, the number of terms of even numbers from 6 to 1500 = 748
This means 1500 is the 748th term.
Finding the sum of the given even numbers from 6 to 1500
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 1500
= 748/2 (6 + 1500)
= 748/2 × 1506
= 748 × 1506/2
= 1126488/2 = 563244
Thus, the sum of all terms of the given even numbers from 6 to 1500 = 563244
And, the total number of terms = 748
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 1500
= 563244/748 = 753
Thus, the average of the given even numbers from 6 to 1500 = 753 Answer
Similar Questions
(1) Find the average of odd numbers from 15 to 57
(2) Find the average of odd numbers from 9 to 493
(3) Find the average of the first 2492 odd numbers.
(4) Find the average of the first 2554 odd numbers.
(5) Find the average of the first 2394 odd numbers.
(6) Find the average of the first 4178 even numbers.
(7) What is the average of the first 37 odd numbers?
(8) Find the average of even numbers from 4 to 86
(9) Find the average of the first 2344 even numbers.
(10) Find the average of odd numbers from 11 to 591