Question:
Find the average of even numbers from 6 to 1604
Correct Answer
805
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 6 to 1604
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 6 to 1604 are
6, 8, 10, . . . . 1604
After observing the above list of the even numbers from 6 to 1604 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 1604 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 6 to 1604
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1604
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 6 to 1604
= 6 + 1604/2
= 1610/2 = 805
Thus, the average of the even numbers from 6 to 1604 = 805 Answer
Method (2) to find the average of the even numbers from 6 to 1604
Finding the average of given continuous even numbers after finding their sum
The even numbers from 6 to 1604 are
6, 8, 10, . . . . 1604
The even numbers from 6 to 1604 form an Arithmetic Series in which
The First Term (a) = 6
The Common Difference (d) = 2
And the last term (ℓ) = 1604
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 6 to 1604
1604 = 6 + (n – 1) × 2
⇒ 1604 = 6 + 2 n – 2
⇒ 1604 = 6 – 2 + 2 n
⇒ 1604 = 4 + 2 n
After transposing 4 to LHS
⇒ 1604 – 4 = 2 n
⇒ 1600 = 2 n
After rearranging the above expression
⇒ 2 n = 1600
After transposing 2 to RHS
⇒ n = 1600/2
⇒ n = 800
Thus, the number of terms of even numbers from 6 to 1604 = 800
This means 1604 is the 800th term.
Finding the sum of the given even numbers from 6 to 1604
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 6 to 1604
= 800/2 (6 + 1604)
= 800/2 × 1610
= 800 × 1610/2
= 1288000/2 = 644000
Thus, the sum of all terms of the given even numbers from 6 to 1604 = 644000
And, the total number of terms = 800
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 6 to 1604
= 644000/800 = 805
Thus, the average of the given even numbers from 6 to 1604 = 805 Answer
Similar Questions
(1) Find the average of even numbers from 4 to 558
(2) What is the average of the first 539 even numbers?
(3) What is the average of the first 1040 even numbers?
(4) Find the average of odd numbers from 9 to 735
(5) Find the average of odd numbers from 9 to 1307
(6) Find the average of the first 511 odd numbers.
(7) Find the average of even numbers from 8 to 620
(8) Find the average of the first 3306 even numbers.
(9) What will be the average of the first 4412 odd numbers?
(10) Find the average of odd numbers from 11 to 1259