Average
MCQs Math


Question:     Find the average of even numbers from 6 to 1892


Correct Answer  949

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 6 to 1892

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 6 to 1892 are

6, 8, 10, . . . . 1892

After observing the above list of the even numbers from 6 to 1892 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 6 to 1892 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 6 to 1892

The First Term (a) = 6

The Common Difference (d) = 2

And the last term (ℓ) = 1892

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 6 to 1892

= 6 + 1892/2

= 1898/2 = 949

Thus, the average of the even numbers from 6 to 1892 = 949 Answer

Method (2) to find the average of the even numbers from 6 to 1892

Finding the average of given continuous even numbers after finding their sum

The even numbers from 6 to 1892 are

6, 8, 10, . . . . 1892

The even numbers from 6 to 1892 form an Arithmetic Series in which

The First Term (a) = 6

The Common Difference (d) = 2

And the last term (ℓ) = 1892

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 6 to 1892

1892 = 6 + (n – 1) × 2

⇒ 1892 = 6 + 2 n – 2

⇒ 1892 = 6 – 2 + 2 n

⇒ 1892 = 4 + 2 n

After transposing 4 to LHS

⇒ 1892 – 4 = 2 n

⇒ 1888 = 2 n

After rearranging the above expression

⇒ 2 n = 1888

After transposing 2 to RHS

⇒ n = 1888/2

⇒ n = 944

Thus, the number of terms of even numbers from 6 to 1892 = 944

This means 1892 is the 944th term.

Finding the sum of the given even numbers from 6 to 1892

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 6 to 1892

= 944/2 (6 + 1892)

= 944/2 × 1898

= 944 × 1898/2

= 1791712/2 = 895856

Thus, the sum of all terms of the given even numbers from 6 to 1892 = 895856

And, the total number of terms = 944

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 6 to 1892

= 895856/944 = 949

Thus, the average of the given even numbers from 6 to 1892 = 949 Answer


Similar Questions

(1) Find the average of the first 4354 even numbers.

(2) Find the average of the first 2379 even numbers.

(3) Find the average of even numbers from 8 to 864

(4) Find the average of the first 2193 odd numbers.

(5) What will be the average of the first 4855 odd numbers?

(6) Find the average of even numbers from 8 to 1180

(7) Find the average of the first 3192 odd numbers.

(8) Find the average of odd numbers from 9 to 1299

(9) Find the average of even numbers from 6 to 334

(10) Find the average of odd numbers from 15 to 707


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©