Question:
Find the average of even numbers from 8 to 168
Correct Answer
88
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 8 to 168
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 8 to 168 are
8, 10, 12, . . . . 168
After observing the above list of the even numbers from 8 to 168 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 8 to 168 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 8 to 168
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 168
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 8 to 168
= 8 + 168/2
= 176/2 = 88
Thus, the average of the even numbers from 8 to 168 = 88 Answer
Method (2) to find the average of the even numbers from 8 to 168
Finding the average of given continuous even numbers after finding their sum
The even numbers from 8 to 168 are
8, 10, 12, . . . . 168
The even numbers from 8 to 168 form an Arithmetic Series in which
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 168
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 8 to 168
168 = 8 + (n – 1) × 2
⇒ 168 = 8 + 2 n – 2
⇒ 168 = 8 – 2 + 2 n
⇒ 168 = 6 + 2 n
After transposing 6 to LHS
⇒ 168 – 6 = 2 n
⇒ 162 = 2 n
After rearranging the above expression
⇒ 2 n = 162
After transposing 2 to RHS
⇒ n = 162/2
⇒ n = 81
Thus, the number of terms of even numbers from 8 to 168 = 81
This means 168 is the 81th term.
Finding the sum of the given even numbers from 8 to 168
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 8 to 168
= 81/2 (8 + 168)
= 81/2 × 176
= 81 × 176/2
= 14256/2 = 7128
Thus, the sum of all terms of the given even numbers from 8 to 168 = 7128
And, the total number of terms = 81
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 8 to 168
= 7128/81 = 88
Thus, the average of the given even numbers from 8 to 168 = 88 Answer
Similar Questions
(1) What is the average of the first 648 even numbers?
(2) Find the average of even numbers from 8 to 1310
(3) Find the average of odd numbers from 7 to 1211
(4) Find the average of the first 2716 even numbers.
(5) Find the average of odd numbers from 11 to 231
(6) Find the average of the first 711 odd numbers.
(7) What is the average of the first 157 even numbers?
(8) Find the average of even numbers from 6 to 1966
(9) Find the average of the first 3284 odd numbers.
(10) Find the average of the first 3264 even numbers.