Average
MCQs Math


Question:     Find the average of even numbers from 8 to 1136


Correct Answer  572

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 8 to 1136

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 8 to 1136 are

8, 10, 12, . . . . 1136

After observing the above list of the even numbers from 8 to 1136 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 8 to 1136 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 8 to 1136

The First Term (a) = 8

The Common Difference (d) = 2

And the last term (ℓ) = 1136

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 8 to 1136

= 8 + 1136/2

= 1144/2 = 572

Thus, the average of the even numbers from 8 to 1136 = 572 Answer

Method (2) to find the average of the even numbers from 8 to 1136

Finding the average of given continuous even numbers after finding their sum

The even numbers from 8 to 1136 are

8, 10, 12, . . . . 1136

The even numbers from 8 to 1136 form an Arithmetic Series in which

The First Term (a) = 8

The Common Difference (d) = 2

And the last term (ℓ) = 1136

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 8 to 1136

1136 = 8 + (n – 1) × 2

⇒ 1136 = 8 + 2 n – 2

⇒ 1136 = 8 – 2 + 2 n

⇒ 1136 = 6 + 2 n

After transposing 6 to LHS

⇒ 1136 – 6 = 2 n

⇒ 1130 = 2 n

After rearranging the above expression

⇒ 2 n = 1130

After transposing 2 to RHS

⇒ n = 1130/2

⇒ n = 565

Thus, the number of terms of even numbers from 8 to 1136 = 565

This means 1136 is the 565th term.

Finding the sum of the given even numbers from 8 to 1136

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 8 to 1136

= 565/2 (8 + 1136)

= 565/2 × 1144

= 565 × 1144/2

= 646360/2 = 323180

Thus, the sum of all terms of the given even numbers from 8 to 1136 = 323180

And, the total number of terms = 565

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 8 to 1136

= 323180/565 = 572

Thus, the average of the given even numbers from 8 to 1136 = 572 Answer


Similar Questions

(1) Find the average of odd numbers from 11 to 485

(2) Find the average of the first 3761 even numbers.

(3) Find the average of the first 1885 odd numbers.

(4) Find the average of even numbers from 8 to 690

(5) Find the average of the first 1315 odd numbers.

(6) Find the average of the first 3108 even numbers.

(7) Find the average of the first 3890 even numbers.

(8) Find the average of odd numbers from 5 to 369

(9) Find the average of even numbers from 12 to 130

(10) Find the average of the first 4760 even numbers.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©