Question:
Find the average of even numbers from 8 to 1288
Correct Answer
648
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 8 to 1288
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 8 to 1288 are
8, 10, 12, . . . . 1288
After observing the above list of the even numbers from 8 to 1288 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 8 to 1288 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 8 to 1288
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1288
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 8 to 1288
= 8 + 1288/2
= 1296/2 = 648
Thus, the average of the even numbers from 8 to 1288 = 648 Answer
Method (2) to find the average of the even numbers from 8 to 1288
Finding the average of given continuous even numbers after finding their sum
The even numbers from 8 to 1288 are
8, 10, 12, . . . . 1288
The even numbers from 8 to 1288 form an Arithmetic Series in which
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1288
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 8 to 1288
1288 = 8 + (n – 1) × 2
⇒ 1288 = 8 + 2 n – 2
⇒ 1288 = 8 – 2 + 2 n
⇒ 1288 = 6 + 2 n
After transposing 6 to LHS
⇒ 1288 – 6 = 2 n
⇒ 1282 = 2 n
After rearranging the above expression
⇒ 2 n = 1282
After transposing 2 to RHS
⇒ n = 1282/2
⇒ n = 641
Thus, the number of terms of even numbers from 8 to 1288 = 641
This means 1288 is the 641th term.
Finding the sum of the given even numbers from 8 to 1288
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 8 to 1288
= 641/2 (8 + 1288)
= 641/2 × 1296
= 641 × 1296/2
= 830736/2 = 415368
Thus, the sum of all terms of the given even numbers from 8 to 1288 = 415368
And, the total number of terms = 641
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 8 to 1288
= 415368/641 = 648
Thus, the average of the given even numbers from 8 to 1288 = 648 Answer
Similar Questions
(1) Find the average of the first 244 odd numbers.
(2) Find the average of the first 2046 odd numbers.
(3) What is the average of the first 1892 even numbers?
(4) What is the average of the first 1064 even numbers?
(5) Find the average of the first 488 odd numbers.
(6) What will be the average of the first 4872 odd numbers?
(7) Find the average of even numbers from 8 to 706
(8) Find the average of the first 2435 even numbers.
(9) Find the average of odd numbers from 13 to 837
(10) What will be the average of the first 4166 odd numbers?